Recent content by linyen416

theoretically it never reaches zero because of the exponential nature of decay, right?

wouldn't there be steady state errors in underdamped oscillation that is unforced?

cyrus, i was asking abotu unforced underdamped oscillation... so in actual physical systems they do reach zero and but theoretically they dont

So for an unforced underdamped oscillation, due to steady state errors that occur in real life, won't decay to zero?

cyrus, i thought damping brings it down to zero faster. also another thing that's troubling me is : for underdamping, overdamping, adn critical damping, do the amplitudes eventually REACH zero IN THEORY or is it that theoretically they only APPROACH zero? thanks

Critical damping provides the quickest approach to zero amplitude for a damped oscillator. With less damping (underdamping) it approaches zero displacement faster, but oscillates around it. With more damping (overdamping), the approach to zero is slower. I got this from hyperphysics but I...

mgb, thanks for ur input! im wondering about underdamped oscillation as well. would displacement theoretically ONLY APPROACH zero?

THEORETICALLY will a SHM eventually reach zero displacemtn or not? If it is DAMPED, amplitude would decrease with time, as would frequency, but would they would reach zero wouldn't they?

so to clear things up: F = -kx refers to restorative force from springs F = -bv refers to the air resistance as the glider moves along and so if we use our amplitude -time graphs to calculated b, we should find that as m increases, b increases because the non-closed system causes extra...

so I shouldn't explain the 'unlcosed-system' quality by saying that the wt force acts in a different vector componenet as the force from springs, but rather I should explain it by saying that the friction is introduced by the weight pushing down, so it's not exactly closed?

SHM --> F = -kx SHM assumes that F is the only force acting on the system, so if we have a mass held between two springs on a linear air track, the F = -kx force refers to the restoring force from the springs? Is that the only thing it refers to? What about air resistance as the gliding...

do you mean that F = -kx only applies before the spring moves? because I've measured spring constants by plotting Force vs. elongation graphs where force = mass hanging from spring *9.8 is that correct

hi astronuc, i still don't understand why it's 2mg

unless there's an equation that relates the individual spring constants to the effective spring constant when the mass is held between two identical springs

So I think one way to get the effective spring constant is to use a pulley somehow.