Recent content by lucphysics

  1. lucphysics

    What is the derivative of (sin x)^sin x?

    Homework Statement f(x)= (sin x)^(sin x) Homework EquationsThe Attempt at a Solution Taking logarithm on both sides I get: ln y = ln ((sin x)^(sin x))
  2. lucphysics

    Kinetic and potential energy (satellite low orbit)

    I'm so grateful for your help, thank you!
  3. lucphysics

    Kinetic and potential energy (satellite low orbit)

    Okay, thank you :)! Another question, for the kinetic and potential energy...should I derivate the equations too?
  4. lucphysics

    Kinetic and potential energy (satellite low orbit)

    Instead of use r as the unknown radius, use r - △r because the statement given says: Due to air drag, the radius of a satellite’s circular orbit decreases from r to r - △r, where the positive quantity △r is much less than r. But maybe I'm wrong and the only way to demonstrate that the...
  5. lucphysics

    Kinetic and potential energy (satellite low orbit)

    Hello, I have this problem statement : "Due to air drag, the radius of a satellite’s circular orbit decreases from r to r - △r, where the positive quantity △r is much less than r. The mass of the satellite is m. Show that the increase in orbital speed is △v = +(△r/2)[(GM/r^3)^1/2]; that the...
  6. lucphysics

    Help with this problem from Mastering Physics (Gravitation)

    Ok, thank you. I think I understand it now.
  7. lucphysics

    Help with this problem from Mastering Physics (Gravitation)

    So, that means that when r decreases the derivative is positive due to the velocity increasement?
  8. lucphysics

    Help with this problem from Mastering Physics (Gravitation)

    Yes, I've made the derivative of v respect r, but what I get it's: v'= - (1/2)•[(GM/sqrt(GM/r^3)] I'm pretty sure I've done something wrong because that isn't the solution given in the problem statement
  9. lucphysics

    Help with this problem from Mastering Physics (Gravitation)

    Homework Statement If a satellite is in a sufficiently low orbit, it will encounter air drag from the Earth's atmosphere. Since air drag does negative work (the force of air drag is directed opposite the motion), the mechanical energy will decrease. If E decreases (becomes more negative), the...
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