Recent content by lulzury

  1. lulzury

    RLC Circuit time for Energy to drop to 20% of initial value

    Thank you for this explanation and for your time in helping me understand this problem.
  2. lulzury

    RLC Circuit time for Energy to drop to 20% of initial value

    Thanks, I think I see. To clarify, do we throw the cosine portion away because @ ## 1/5 U_0 ## we'll be at a local peak for the decaying energy in the RLC circuit? How do we know this?
  3. lulzury

    RLC Circuit time for Energy to drop to 20% of initial value

    Sorry that was a mistake on my part. That should be: ## 0.2 = e^{\frac{-Rt}{L}}\cos^2(\omega't) ## ## cos(\omega t) = 1 ## when the energy of the capacitor is maximum which is why I dropped it on the equation for ## U_0 = \frac{Q^2}{2C} ##
  4. lulzury

    RLC Circuit time for Energy to drop to 20% of initial value

    Homework Statement In an oscillating series RLC circuit, with resistance R and inductance L, find the time required for the maximum energy in the capacitor during an oscillation to fall to 1/5 its initial value. Assume q = Q at t = 0 Homework Equations ## U(t) =...
  5. lulzury

    Photon Flux vs. Intensity: Which equation should be used to solve this problem?

    Thanks TSny, I checked the units of both photon flux and intensity and got different units. It's so weird that my book decided to use the same symbol for different quantities.
  6. lulzury

    Photon Flux vs. Intensity: Which equation should be used to solve this problem?

    Homework Statement A sodium lamp emits light at the power P = 130 W and at the wavelength λ = 570 nm, and the emission is uniformly in all directions. (b) At what distance from the lamp will a totally absorbing screen absorb photons at the rate of 1.00 photon /cm^2s? Homework Equations 1...
  7. lulzury

    Small Angle Approximation in Single Slit Interference

    mfb, that makes sense thank you! So in this case tan(θ) = y/D ## θ = \arctan(\frac{y}{D}) ## ## θ = \arctan(\frac{8.73*10e-3}{2}) ## θ = 0.00436 rad ~ 0.25 degrees That is a very small angle, so I can use a small angle approximation here!
  8. lulzury

    Small Angle Approximation in Single Slit Interference

    Homework Statement A monochromatic light source is used with a double slit to create an interference pattern on a screen that is 2.00 meters away. If the 2nd bright spot is observed 8.73 mm above the central maximum, can the small angle approximation be used? Show and/or explain your reasoning...
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