Thanks, I think I see. To clarify, do we throw the cosine portion away because @ ## 1/5 U_0 ## we'll be at a local peak for the decaying energy in the RLC circuit? How do we know this?
Sorry that was a mistake on my part. That should be:
## 0.2 = e^{\frac{-Rt}{L}}\cos^2(\omega't) ##
## cos(\omega t) = 1 ## when the energy of the capacitor is maximum which is why I dropped it on the equation for ## U_0 = \frac{Q^2}{2C} ##
Homework Statement
In an oscillating series RLC circuit, with resistance R and inductance L, find the time required for the maximum energy in the capacitor during an oscillation to fall to 1/5 its initial value. Assume q = Q at t = 0
Homework Equations
## U(t) =...
Thanks TSny, I checked the units of both photon flux and intensity and got different units.
It's so weird that my book decided to use the same symbol for different quantities.
Homework Statement
A sodium lamp emits light at the power P = 130 W and at the wavelength λ = 570 nm, and the emission is uniformly in all directions. (b) At what distance from the lamp will a totally absorbing screen absorb photons at the rate of 1.00 photon /cm^2s?
Homework Equations
1...
mfb, that makes sense thank you!
So in this case tan(θ) = y/D
## θ = \arctan(\frac{y}{D}) ##
## θ = \arctan(\frac{8.73*10e-3}{2}) ##
θ = 0.00436 rad ~ 0.25 degrees
That is a very small angle, so I can use a small angle approximation here!
Homework Statement
A monochromatic light source is used with a double slit to create an interference pattern on a screen that is 2.00 meters away. If the 2nd bright spot is observed 8.73 mm above the central maximum, can the small angle approximation be used? Show and/or explain your reasoning...