"It is left as a problem for the reader to show that if [S,T] commutes with S and T, then [e^{tT}, S] = -t[S,T]e^{tT}
I'm not sure if I'm missing something here, but i don't even see how it is possible to arrive at this answer.
I get:
[e^{tT}, S] = e^{tT}S - Se^{tT}
Then using the fact...