Recent content by makhoma

Wow that was silly easy. Thanks a bunch for your help arkajad.

Interesting thought there...I'll take a look at that.

vector identity?? Homework Statement The text that I'm reading has a line that reads \left(\mathbf{b}\mathbf{k}\cdot-\mathbf{b}\cdot\mathbf{k}\right)\mathbf{v}=\omega\mathbf{B} and I'm not sure what it means by \mathbf{b}\mathbf{k}; it's clearly not the dot product nor the cross product. A...

http://en.wikipedia.org/wiki/Work_(physics)#Force_and_displacement" It says here (as well as my textbooks) W=\mathbf{F}\cdot\mathbf{d}=Fd\cos\theta I have no x component of F. I have only the magnitude \left|\mathbf{F}\right|=k/y I don't think I am using that \theta is the same as the angle...

I was only given the magnitude, so I figured I would have to use F\cos\theta dr instead of \mathbf{F}\cdot d\mathbf{r}. :biggrin: This is what happens when you copy the previous line & change only the answer. I had used k/r in the previous two parts, but I am thinking I need to use...

Homework Statement A particle in the xy plane is attracted toward the origin by a force of magnitude F=k/y (a) Calculate the work done when the particle moves from point (0,a) to (2a,0) along a path, which follows two sides of a rectangle consisting of a segment parallel to the x axis from...

I think I found an error in what my professor did in class. We have a line that reads \int_0^ady\int_0^bdz\sqrt{\frac{2}{a}}\sin\left[\frac{n_y'\pi y}{a}\right]\sqrt{\frac{2}{b}}\sin\left[\frac{n_z'\pi z}{b}\right]\Phi_0=A_{n_y'n_z'} And it should read...

I was in my Electrodynamics lecture last week, still working the Laplacian and Poisson equations, when we discussed an infinite parallelpipid (infinite in the x direction, length a and b in the y and z direction respectively) with a potential of \Phi=\Phi_0 at x=0 plane and every other face...

The electric field of the point charge is \mathbf{E}=\frac{1}{4\pi\varepsilon_0}\cdot\frac{q(0\mathbf{x}+0\mathbf{y}+(1-m)\mathbf{z})}{\left((0)^2+(0)^2+(1-m)^2\right)^\frac{3}{2}} where I put the reference point at a position m, between 0 and 1 on the z-axis. This makes the force equation...

Homework Statement The z=0 plane is covered with the uniform surface charge density, \rho_s=10^{-9}, while at the same time the point charge q=10^{-9} is located at (0,0,1). Where can an electron be place so if released, it will not move. Homework Equations...