Recent content by MarchON

Haha, not worth it. And I have no idea why he made the solution so overly confusing.

The answer my professor has given is 23.9 m/s. o_O

0 because it's the x direction. Right?

Ok, well my number has gotten smaller, but it is still not the 23.9 m/s that is apparently the answer. I solved for time and got 4.5 seconds, and then using Δx=v0t+(1/2)(a)t2 I got 26.7 m/s

0? Anyway, I have the solution in front of me. It has a bunch of trig which I do not understand. The solution used the "standard coordinate system with the origin at the initial position of the car." x = x0 + (v0,x)t+(1/2)(ax)t2 = 0 + v0(cosθ)t+(1/2)(0)t2=v0(cosθ)t

I did not post that part because I understood it. I was just letting you know, so people don't try to factor in air resistance mathematically.

I thought that v was v final which is 0 with regards to the vertical portion of its fall? I thought v0 was the initial velocity which is what I am trying to find.

Air resistance being negligible is part of the problem and becomes in incorrect assumption for part C. It's there to show us that the final answer, whatever it is, will be inaccurate... I am having trouble getting to that final answer.

Homework Statement A car drives off a cliff that is 100m high. It has to land in water and the water starts 30m away from the cliff. Its goal is to land 90m into the water. How fast must the car be going to land at that point in the water. Air resistance is negligible. v=0 v0=? a= -9.91m/s2...

I don't understand how. Is there any way (and I know this is no easy task) to break down the algebra step by step for me? Also, I made a mistake with the resultant equation in my first post. It's actually mw = -(mcccΔTc)/cwΔTw - Lf,w (no - mwLf,w) I realize that ends up being the same thing...

Latent heat of fusion is in the picture because the water is going from a liquid to a solid. It freezes when it hits the car, then at a certain point it doesn't because the car warms up to 0 degrees. And I don't know what's up with the equation, but that's what my professor's solution says...

I'm trying to determine how much water it takes to raise a car's temperature from -25°C to 0°C. The water is at 10°C. What I apparently need to have set up is: -ΔUint,water = ΔUint,car -(mwcwΔTw) - mwLf,w = mcccΔTc The resultant rearranged equation looking for mass of water gives this: mw =...

Ohh thank, you! Saved me.

Trombooonnneee! The most sound physics straight forward instrument haha.

D=m/V I've know that there is water displacement for volume and also V=4/3πr2 (object is a ball) Is there any other way to determine density that does not involve directly finding volume? I figure that if the object floats (and is not hollow) it is less dense than water, and if it sinks it is...