Recent content by mathgeek69
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Is the Limit of sqrt(x+sinx)ln(x) as x Approaches Zero Solvable?
It approximates cos(x+ (pi/2)) ?- mathgeek69
- Post #5
- Forum: Calculus and Beyond Homework Help
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Is the Limit of sqrt(x+sinx)ln(x) as x Approaches Zero Solvable?
as sin(x) approaches 0 as x approaches 0. That didn't help me as I still resolve to 0*(-∞) but as you say we need a different approach. I did try to do" let y = (x+sin(x))^2 " and try to take that approach but I didnt know what to do after as now I am introducing y all of a sudden and don't...- mathgeek69
- Post #3
- Forum: Calculus and Beyond Homework Help
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Lim of trig functions. Does it exist?
So 0/0 = Limit doesn't exist ?- mathgeek69
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Lim of trig functions. Does it exist?
1. Does the limit exist of the following: lim as x→ 1- ((cos^-1(x))/(1-x)) 2. Homework Equations : 3. The Attempt at a Solution : lim as x→ 1- ((cos^-1(x))/(1-x)) = lim as x→ 1- (cos^-1(x))/ lim as x→ 1-(1-x) Let y = 1-x lim as y→0 (cos^-1(1-y)) / lim as y→0 (y) =...- mathgeek69
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- Functions Trig Trig functions
- Replies: 7
- Forum: Precalculus Mathematics Homework Help
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Is the Limit of sqrt(x+sinx)ln(x) as x Approaches Zero Solvable?
1. lim as x->o+ ( (sqrt(x+sinx))(lnx)) 2. Homework Equations : [PLAIN]http://www.math.oregonstate.edu/home/programs/undergrad/CalculusQuestStudyGuides/SandS/lHopital/Laws/multiplication_law.gif 3. The Attempt at a Solution : lim as x->o+ ( (sqrt(x+sinx))(lnx)) = lim as x->o+...- mathgeek69
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- Limit
- Replies: 8
- Forum: Calculus and Beyond Homework Help
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How Does the Limit of tan^-1(1/(x-pi))/(pi-x) Behave as x Approaches pi?
The limit division law says if lim of f(x) and g(x) exists and if lim of g(x) isn't 0 then... Because in my answer the denominator reaches 0, the limit of entire question DOES NOT EXIST ?- mathgeek69
- Post #7
- Forum: Precalculus Mathematics Homework Help
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How Does the Limit of tan^-1(1/(x-pi))/(pi-x) Behave as x Approaches pi?
I don't know where you got the u from. This is what I got: Let y= x- \pi so the problem becomes \lim_{y\to 0} \frac{tan^{-1}(1/-y)}{y} now I do see that the denominator goes to 0 but the numerator does not. This means the limit does not exist ?- mathgeek69
- Post #6
- Forum: Precalculus Mathematics Homework Help
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How Does the Limit of tan^-1(1/(x-pi))/(pi-x) Behave as x Approaches pi?
oops, I meant to say- mathgeek69
- Post #4
- Forum: Precalculus Mathematics Homework Help
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Find the solution if it exists.
sorry it was a typo. instead of 14x i meant to write 4x... thanks.- mathgeek69
- Post #6
- Forum: Precalculus Mathematics Homework Help
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How Does the Limit of tan^-1(1/(x-pi))/(pi-x) Behave as x Approaches pi?
1. lim as x→+pi ##\frac{tan^-1(1/(x-pi))}{pi-x}## Homework Equations: lim(x/y)= lim (x) - lim (y) The Attempt at a Solution: umm don't know where to go from here... lim as x→+pi [tan^-1(1/(x-pi))] - lim as x→+pi (pi-x)- mathgeek69
- Thread
- Limit
- Replies: 8
- Forum: Precalculus Mathematics Homework Help
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Find the solution if it exists.
Sorry that's what I meant. It was a typo. So my x is a long decimal answer. Is there any way of finding a preciser and a more clear answer ?- mathgeek69
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Find the solution if it exists.
1. ln(5x+6)+ ln(x-2)=1 2. Homework Equations : log(xy)= log(x)+ log(y) 3. The Attempt at a Solution : ln(5x+6)+ ln(x-2)=1 ln((5x+6)(x-2))=1 ln(5(x^2)-14x-12)=1 e^(ln(5(x^2)-14x-12)) = e^1 5(x^2)-4x-12=e 5(x^2)-4x-(e-12)=0 use quadratic formula to find x and I get x=2.1617 I don't think I am...- mathgeek69
- Thread
- Replies: 5
- Forum: Precalculus Mathematics Homework Help
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What is the limit of (3x³ + cos(x)) / (sin(x) - x³) as x approaches infinity?
so ... $$\lim_{x\rightarrow\infty}\frac{3x^3+\cos{x}}{\sin{x}-x^3}=\lim_{x\rightarrow\infty}\frac{3x^3(1+\frac{\cos{x}}{3x^3})}{-x^3(-\frac{\sin{x}}{x^3}+1)}$$ = -3 I GET IT! @Mandelbroth. your new edit was helpful! VERY HELPFUL Cheers,- mathgeek69
- Post #10
- Forum: Precalculus Mathematics Homework Help
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What is the limit of (3x³ + cos(x)) / (sin(x) - x³) as x approaches infinity?
ok then. When applying the squeeze theorem, how are you concluding to this?##\lim_{x\to\infty} \frac{3x^3+\cos(x)}{\sin(x)-x^3}=-3##- mathgeek69
- Post #9
- Forum: Precalculus Mathematics Homework Help