Recent content by Matty R
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Thermodynamics: Proofs of work done on/by gas during adiabatic process
Thank you very much for your help. I'm feeling quite embarrassed now, though most of the threads I've created here have been about really basic mistakes, so I should be used to it. :rolleyes:- Matty R
- Post #5
- Forum: Introductory Physics Homework Help
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Thermodynamics: Proofs of work done on/by gas during adiabatic process
Thanks for the reply. So, erm, is this true: W = - \frac{P_f V_f - P_i V_i}{1 - \gamma} = \frac{P_f V_f - P_i V_i}{\gamma-1} = \frac{P_i V_i - P_f V_f}{1 - \gamma}- Matty R
- Post #3
- Forum: Introductory Physics Homework Help
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Thermodynamics: Proofs of work done on/by gas during adiabatic process
Hello I'm really confused with this and would appreciate any help. Homework Statement a) Show that the work done on a gas during a quasistatic adiabatic compression is given by: W = \frac{P_f V_f - P_i V_i}{\gamma - 1} b) Show that the work done by a gas during a quasistatic...- Matty R
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- Adiabatic Adiabatic process Gas Process Proofs Thermodynamics Work Work done
- Replies: 4
- Forum: Introductory Physics Homework Help
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Surface Integral: dot product of two unit vectors
Yup, my example is incorrect. It switches to polars coordinates on the next line and has the root sign there. I'm so rusty with this. I'm stuggling to do the division. :redface: EDIT Its coming back now.- Matty R
- Post #6
- Forum: Calculus and Beyond Homework Help
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Surface Integral: dot product of two unit vectors
Wow. Thanks for the replies. :smile: I knew it would be something straightforwards like that. I keep overthinking. I completely agree about the notation. The method I've been using looks very messy, so I'll give the method you prefer a go. Just past the bit where I was stuck, the...- Matty R
- Post #4
- Forum: Calculus and Beyond Homework Help
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Surface Integral: dot product of two unit vectors
Hello. :smile: I understand most of the work involved with these types of questions, but there is one point in an example I'm following that I don't understand. Homework Statement Evaluate: I = \int{(z^2)}dS over the positive quadrant of a sphere, where (x,y > 0). Homework...- Matty R
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- Dot Dot product Integral Product Surface Surface integral Unit Unit vectors Vectors
- Replies: 5
- Forum: Calculus and Beyond Homework Help
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Finding the de Broglie wavelength from momentum
Thanks for the replies. :smile: Sorry. I'm still a bit confused. To convert MeV/c to SI Units, do I just multiply the number (ie: 300) by "M" multiplied by "eV"? I thought I was supposed to work it out as SammyS did, but doing that gives a different answer to the solutions. EDIT...- Matty R
- Post #4
- Forum: Introductory Physics Homework Help
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Special Relativity: Which notation to use
Never mind. I worked out the difference. First equation: L_{0} = Proper Length L = Length in frame moving relative to the rest frame. Second equation: L = Proper Length L' = Length in frame moving relative to the rest frame.- Matty R
- Post #2
- Forum: Introductory Physics Homework Help
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Finding the de Broglie wavelength from momentum
Homework Statement What is the de Broglie wavelength of a neutron traveling with a momentum equal to 300 \frac{\text{MeV}}{\text{c}}? Homework Equations \lambda = \frac{h}{p} The Attempt at a Solution p = \frac{300 \cdot \left( \left(1\times10^6 \right) \times...- Matty R
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- De broglie De broglie wavelength Momentum Wavelength
- Replies: 3
- Forum: Introductory Physics Homework Help
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Integration with Reduction Formula
Yup. I've got it now. I still had a hiccup, with (m - 1) multiplied by a couple of terms, I tried to fully expand it. I think I understand it now. I found an example applying sin^m(x) in my lecture notes, so I'll use that for applying this integral. Thanks for your help. :smile: I...- Matty R
- Post #6
- Forum: Calculus and Beyond Homework Help
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Integration with Reduction Formula
Thanks for the reply. :smile: Part of my problem is that I don't understand how to incorporate the limits for something like sin^{m-1}(x). I_{m} = \int^{\frac{\pi}{2}}_{0} \left(cos(x)cos^{m-1}(x) \right)dx Integration by parts I_{m} = \left[sin(x)cos^{m-1}(x)...- Matty R
- Post #3
- Forum: Calculus and Beyond Homework Help
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Integration with Reduction Formula
Hello :smile: I was hoping someone could help me with this. I'm going round in circles and don't understand how to solve it. Homework Statement The integral I_m is defined as: I_m = \int^{\frac{\pi}{2}} _{0} (cos^m(x))dx where m is a positive integer. By representing cos^m(x)...- Matty R
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- Formula Integration Reduction
- Replies: 5
- Forum: Calculus and Beyond Homework Help
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Differentiating Complex Exponentials
Brilliant. Thank you very much. :smile:- Matty R
- Post #5
- Forum: Calculus and Beyond Homework Help
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Differentiating Complex Exponentials
Hiya tim. Nice to see you again. :smile: That makes perfect sense. I've managed to get the same answer as the solutions now, and I was wondering if you'd be so kind as to confirm what I did. For the real part: 2e^{-t} \left[(-1 \times cos(3t)) + (3i \times isin(3t) \right] For the...- Matty R
- Post #3
- Forum: Calculus and Beyond Homework Help
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Differentiating Complex Exponentials
Hello :smile: I'm currently using past papers to revise for January exams, and I've found a bit of a problem with something I thought I was okay with. Homework Statement The position at time t of a particle undergoing damped oscillations is given by: x = 2e^{-t}\sin(3t). Express...- Matty R
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- Complex Differentiating
- Replies: 4
- Forum: Calculus and Beyond Homework Help