Recent content by MaxL

3 is from wave dynamics...I don't know if it has a name, but it describes the speed of a wave in terms of its wavelength and frequency or period. 5 relates angular frequency to ordinary frequency. 2 and 6 describes the acoustic harmonics of a tube...I think 2 describes an open tube, 6 a tube...

I read your post again and I guess I misunderstood your question. So you've imagined a ball of water that is subject to gravity? That seems impossible, but we could make a water balloon that was about the same...then I say, because any bits of ice that form would float to the top, the...

Oh, that's an interesting question. Well, first off, I don't think your model of how a lake freezes is right. Convection currents may or may not be present in freezing lakes--I don't know. But another effect would overwhelm any convection currents: The buoyancy of ice. Ice will form...

Hahaha, oh man that's hilarious.

Really interesting! Thanks for bringing this to my attention! I'm not familiar with this problem, so I'm not offering an answer, but here's what I did: First restate u^i*v = e^(ln(u)*i*v)=u If you take the x derivative of both sides, you get i*e^(ln(u)*iv)*(u'v/u + v'ln(u))=u'...

So I've always done simple ODEs by the method of separation of variables. You know, dy/dx = A*y dy/y = A*dx IndefiniteIntegral[1/y dy] = IndefiniteIntegral[A dx] ln(y) = A*x + Constant y = Constant*e^(A*x) It's easy to remember and it usually works. A lot of the PDEs I know how to do...

So you know the KE of both objects before the collision, and you want to know the KE of both objects after the collision. There's two unknowns, so you'll need two equations. You got one, which comes from the conservation of momentum. What's the other equation? (Hint: It comes from the fact...

Drawing a picture is always a good way to start.

Vector addition is commutative: (A+B) + C = A + (B+C). So yeah, that should work.

When I was a little kid, I met a gemologist who showed me a cool trick with a ring he'd bought for his wife. When he submerged it in water, the crystal disappeared! As I now know, this crystal had an index of refraction of 1.33. Anyone know what this crystal is and/or how I can get my...

It does not. It would if the jumper and the thing they were jumping off of had equal mass (and I'm assuming you meant the first jumper, and 2.5m/s referred to the velocity). As for the velocity of the cart relative to the ground after the first jumper jumps: You know the initial velocity of...

Ah, I just did it a different way and got .25 to the north. Okay, so it seems the mistake we were making was in treating the velocity of the jumpers incorrectly. We were saying 5 m/s was the velocity of the jumper relative to the cart before the jump. So if we were standing off the tracks...

The answer I got was 5/12 m/s. I'm pretty confident about it. What's the [N]?

Hey, no problemo!

Yep!