What is the solution to the Tricky Collision Problem?

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Homework Statement


A small hard block of mass 3m is suspended from a thread of length L. A second block of mass m is located on an incline, originally at rest, a height y above the level of the large mass. When the smaller block is released it slides, without friction, down the ramp, and then collides elastically with the larger block. The large block swings around so that the tension in the string just barely drops to zero at the top of the loop. The small block slides back up the ramp, rising to a maximum vertical height h.

Homework Equations


conservation of momentum: pi=pf
p=mv

The Attempt at a Solution


...help to get started please!??
 
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Drawing a picture is always a good way to start.
 
I've done a picture, and have a basic understanding that I should use conservation of energy to find velocity of the block at bottom of incline. Then I need conservation of momentum in an elastic collision to find velocity of ball on string...(?) How does this help me find the new h and the L?
 
So you know the KE of both objects before the collision, and you want to know the KE of both objects after the collision. There's two unknowns, so you'll need two equations. You got one, which comes from the conservation of momentum. What's the other equation? (Hint: It comes from the fact that the collision is elastic)
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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