Recent content by Mbaboy

Homework Statement I will present a vary simplified version of the problem I am trying to model. Essentially I took 100 people and split them into 10 groups. To each group I tried to sell them a product. To the first group I priced the product at $5, to the second I priced it at $15, to the...

Ok, I think I get it. Thanks a lot. And I agree there should be a negative in there.

Ok, so I updated the original post and defined the equations a little better. Eventually in the problem we are suppose to prove \mu_i=T\left( \frac{\partial S}{\partial n_i}\right)_{U,V,n_j\not=i} =\left( \frac{\partial U}{\partial n_i}\right)_{S,V,n_j\not=i} =\left(...

So I am guessing that you are asking for the equation of motion for the pendulum. Start out with the first law for torque T = I\alpha For the pendulum the moment of intertia is I = L^2m So what are the torques on the pendulum? If you draw out the free body diagram (or look on...

Homework Statement Derive the following: \mu_i=T\left( \frac{\partial S}{\partial n_i}\right)_{U,V,n_j\not=i} \mu_i is the chemical potential of the ith component G is the Gibbs free energy Homework Equations dU = TdS - PdV + \sum_i \mu_i dn_i \mu_i =...

Ah ok it all makes very good sense. The only thing I cannot grasp is how there are k-1 orderings. The way I see it there is only 1. Consider for k=4 X_1>X_2>X_3<X_4 There is only 1 way to order it such that the condition still holds, or am I missing something? Edit: Ok, I see for the random...

Homework Statement Let X_1, X_2,... be independent identically distributed continuous random variables. We call n the first time of increase if X_1>X_2>X_3>...>X_{n-1}<X_n Let N be the time until the first increase. Show that E[N]=e. Homework Equations Given for a discrete random variable...

Does anyone know why I can find a printable sheet with all the common derivatives? I know most off the top of my head, but I need to review a few like logs and inverse trigonometric functions. I need something to use as a good study sheet. Thanks.

So what I'm doing is mgh=(mv^2)/2 and h can be represented as the chord length 2rsin(.5A) times cosA. So basically the answer is one huge expression that I don't feel like writing. I still don't understand what you are saying there. Circular motion can't cause centripetal force. Objects in...

Why is it gcosA and not mgcosA. Also, is Fcp the centripetal force? If so what is causing it? How can you solve for it because A can't be in terms of Fcp.

I was always told the normal force is perpinducar to the surface, so it would be pointing out from the center. Maybe I didn't clarify the problem well enough, but it is as if the skier is skiing off the top of a sphere. Can you explain how the normal is causing the centripetal acceleration?

I don't understand. The normal force is perpendicular to the surface. So if they are both the same, the skier will have no centripetal acceleration.

Well I know that in order to go airborn the normal force is equal to zero. But when it is not zero, the component of the weight towards the center of the slope must be greater than the normal. I'm stuck from there.

There is a circular slope that a skier is going down. He is at the top. If he goes just fast enough to start down the slope, at what angle to the center of curvature does the skier go airborne? I'm not sure if its asking for an exact angle or what. Any help or shove in the right direction is...

Sorry, my last post was sloppy. That was the equation I used. But when I did that, my a=9 ft/s/s which gives the distance as about 8 feet. The actual distance was about 45 feet. Normally, I would conclude my experimental data is off, but its seems way too off.