Recent content by meesa

The velocity would be constant, since acceleration is zero. What I wrote in my first post is the exact question.

Just saw that and edited my post right before yours came though. r' is the velocity. A general approach will work, if you can do it without being too abstract. Appreciate your time.

The acceleration would be zero. We're in mystical space where everything is perfect with lovely numbers. Fixed the y derivative. I've seen full solutions here before. The answer is 1 according to the back of the book.

Homework Statement The position of a spaceship is (3 + t, 2 + ln(t), 7 - \frac{4}{t^2 + 1}) and the coordinates of the space station are (6, 4, 9). The captain wants the spaceship to coast into the space station. When should the engines be turned off? Homework Equations r' = (1, \frac{1}{t}...

But the apparatus, which would begin to move in the time it takes for the second to propagate, would stop moving. I need to know how/why. I realize once it passes the other charged object it still keeps going.

It's all conceptual, and thus in space. All I need is why the apparatus stops moving once the second field has propagated. I'm sure the reason doesn't differ much depending on how the apparatus is designed in the conceptual world.

Two wires, two point charges, two things that are charged. This is for a final, and I'm having difficulty remember all the details of what was discussed, which is why I'm having trouble remembering why. I think the teacher did it with two wires connected to a non conductive material. After the...

The charges are connected. Forgot to put that originally.

If an electric charge is placed into an electric field of a charge that has been around for a while, it will start to move until equilibrium is reached, or until it's field has propagated out as far as the other charge. Note that the charges are connected by some non-conductive material...