Recent content by Meowzers

Delta U is 0 in a full cycle since it returns to its initial state. So the work done is equal to the change in heat. Thanks so much for your help! :)

Homework Statement The pressure-volume graph shows an engine cycle with four processes: two isobaric, and two constant-volume. The engine uses 0.800 mol of an ideal monatomic gas as its working substance. For one engine cycle, calculate (a) the heat added to the gas, (b) the heat removed...

Nevermind, I got it. Thanks for the response!

So, I use the specific heat equation to calculate the heat released by the steam? Q=cmT (steam) Q=(4178 J/kg*K)*(m)*(100-25) Q=13350*m Then, I just added the 2 Q's together and set it equal to the specific heat stuff of the water. (2.26*10^6)(m) + 313350m = (4178)(1.8)(3) 2573350m = 22561.2 m...

Homework Statement Steam at 100°C is injected into 1.8 kg of water at 22°C in a well-insulated container, where it condenses and mixes with the existing water, reaching thermal equilibrium. If the final temperature of the well-mixed water is 25°C, what is the mass of the injected steam...

The equation is straight from my book - I only forgot to write out m/s2 instead of m/s. Period of pendulum: T=2*pi*(square root of (length of pendulum/g) 4.7s = 2*pi*(square root of (0.8s/g)) Square both sides and divide both sides by 4pi^2 to get: .5595 = 0.85/g g = 1.5191 m/s2...

Can anyone explain please?

Well I tried to use one of them, and I got 2.016 m as the displacement. It just doesn't make sense to me that with using the same amount of force on a different planet with less acceleration due to gravity would make the ball reach a lower height.

"On the moon of a distant planet, an astrnaut measures the period of a simple pendulum, 0.85m long, and finds it is 4.7 seconds. Back on Earth, she could throw a rock 13m straight up (while wearing her spacesuit). With the same efoort, how far up can she throw the same rock at her present...

Thanks for all your help :)

Well, in my force diagram, the 22 degree angle is right across from the downward force of the boy's hand. I guess they're just mirror images of each other... So, the force of both the hand and the sack are Fsin(theta)? torque of hand + torque of wall = 0 rFsin(theta) + rFsin(theta) = 0...

I just want to make sure that I approached the following problem correctly: A boy carries a sack on one end of a very light stick that is balanced on his shoulder, at an angle of 22.0 degrees up from the horizontal. The mass of the sack is 7.00 kg, and it sits 1.20 m from his shoulder. If his...

What does the moment of inertia depend on? -Angular velocity -Shape of the object -Location of axis of rotation -Mass Well, I think the location of the axis of rotation matters because it sets a reference point. I'm not sure about the others. Doesn't it also depend on how the mass of...

Thank you very much for your help!

So, I am trying to grasp the concept of conservation of momentum. I need someone to just look over my reasonings (and correct me for any errors) for the following situation. Let's say there are two objects, A and B. A is moving and then it has a head-on collision with object B, which is...