Recent content by Midy1420

right method, and you won't have to multiple both by 2 since the ratio will cancel that out anyway

not sure if what I'm thinking is correct but its an idea: a= dv/dt so we know dv/dt = -.05v^2. We can integrate that to get the velocity function. once we have the velocity function we can integrate again since v(t) = ds/dt. we have initial conditions. its just an idea.

use the property that Ln(a^b) = b Ln(a), Ln(e) = 1, Ln(e^a) = a

right F = Fx + Fy where Fx = Fcos(theta) + FSin(theta) relative to the coordinate system. Once you find all the components you can add all the Fx's and Fy's

yup, e^(2lnx) = e^(ln (x^2)) = x^2

You're on the right track. You are looking for the initial velocity of ball B. We know the displacement (15ft), we know the acceleration (-32.2 ft/(s^2)) and you found the time it takes to travel this distance (1.115 s) it takes to reach that value. Which equation would you chose, to solve...

q1 is to the right of the test charge (placed at the origin) and q2 is to the left of it.. draw a force diagram to see

The direction of the E-field is taken to be the direction of the force it would exert on a positive test charge so when you draw a diagram with a positive test charge how would the forces from the q1 and q2 be acting on it? In the same direction or opposite?

Force is a vector therefore has magnitude and direction. Break the forces into its components.

if i remember, the atom becomes more stable when a subshell is either fully filled/half filled. so with the 3d6 loses one electron to make it half full and places it in the 4s subshell to make that half filled as well making the atom more stable.

break the integral into two parts one from -inf to 0 and then 0 to inf...if any of those two intregrals diverge then the whole thing diverges

I was wrong i thought for some reason order mattered when choosing. Sorry

once you choose one person then you can't choose them again...therefore if you were to choose 3 people out of 10...you have 10 to choose from first, then 9 to choose from and 8 for the third choose. Therefore you have 10 x 9 x 8. I hope that's right?

I am not really sure of how to do this but looking at your last line, I think you messed up taking the second derivative of x^2/(1-x) since you need to use the quotient rule, the (1-x) should be squared on each derivative

did you take into account that when the sandbag begins to fall it has an upward velocity of 5m/s?