Recent content by MilenaMath
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What is the probability of getting 1,2,3,4 when 5 dice are thrown and
I need to get exactly 1,2,3,4(order doesn't matter) and the fifth dice can be whatever number but 5- MilenaMath
- Post #3
- Forum: Calculus and Beyond Homework Help
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What is the probability of getting 1,2,3,4 when 5 dice are thrown and
What is the probability of getting 1,2,3,4 when 5 dice are thrown and one of them is not 5.(the order of 1,2,3,4 doesn't matter) I am really confused: So I computed chances of getting correct numbers that is 1/6^4 times 5/6,then I multiply this by 4 times 5! Am I right?- MilenaMath
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- Dice Probability
- Replies: 4
- Forum: Calculus and Beyond Homework Help
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Calculating Total Spring Constant of Parallel Springs
I found out my mistake: So the right way to proceed is We apply force ##F_x## to the spring and let's assume it stretches to length ##x_n-L## then we have ##F_x=k(x_n-L)## .Then we cut the spring into half and both of them would stretch to##x/2## length when ##F_x## force is applied but both of...- MilenaMath
- Post #7
- Forum: Introductory Physics Homework Help
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Calculating Total Spring Constant of Parallel Springs
My solution was: I assumed the F=kx,k is the spring constant of the initial spring,then I said ##k_1= F/(x/2)## so is ##k_2## and thus ##k_1=k_2=2k => k_t=4k## But he says my mistake is that I can't say ##k_1= F/(x/2)## but the rest is ok- MilenaMath
- Post #5
- Forum: Introductory Physics Homework Help
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Calculating Total Spring Constant of Parallel Springs
But the correct answer is 4K,I did the same thing,but the professor says 4K,I can't find the mistake- MilenaMath
- Post #3
- Forum: Introductory Physics Homework Help
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Calculating Total Spring Constant of Parallel Springs
A spring with spring constant k and of unstretched length L is cut in half and both parts are put side by side. Determine the total spring constant of the parallel springs. Can anyone explain me the solution to this.- MilenaMath
- Thread
- Law
- Replies: 7
- Forum: Introductory Physics Homework Help
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Mechanics: Straight line motion
True! then I get constant as b/[-2T^2]. Thank you! (Since car is initially at rest I assume v(0)=0)- MilenaMath
- Post #3
- Forum: Introductory Physics Homework Help
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Mechanics: Straight line motion
1. A car is sitting at a stop light and then accelerates from rest when the light turns green.The acceleration of the car is a combination of forward acceleration but also slowing down due to drag forces.The final total accelaration of the car has the form a(t)=b/(t+T)^3 with constants b=2000 m...- MilenaMath
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- Line Mechanics Motion Straight line
- Replies: 2
- Forum: Introductory Physics Homework Help