Recent content by mizzy

Homework Statement A rectangular waterproof air mattress is 2.0m long, 0.50mwide and 0.08m thick. It has a mass of 2.0kg and is supporting an additional mass of m, while floating in the water, calculate the mass, m, assuming the density of water is 1000kg/m^3 and density of air is...

Thanks

so, mgh = mc(T-Ti) then solve for Tf? therefore, mgh = mc(Tf - Ti) gh = cTf - cTi gh + cTi = cTf gh/c + Ti = Tf

Thanks for you help! =)

So in state 1 there is potential energy, no kinetic energy. State 2 there's kinetic energy, where v is half of the max speed and there's potential energy and that's when we solve for x.

at state 2, is it half the compressed state?

k. i got the answer, the max speed is 0.28m/s. The next part of the question is, for what value of x does the speed equal one-half the maximum speed. What i did was to solve for x with v = 1/2(max speed) I got the answer wrong. Can someone point out where i went wrong?

so 1/2mv^2 = 1/2kx^2 v = square root (kx^2/m)

sorry not kinetic energy but potential energy.

so KE + KEs = 0 1/2mv^2 + 1/2kx^2 = 0 solve for v?

Homework Statement A 0.40kg object connected to a light spring with a force constant of 19.6N/m oscillates on a frictionless horizontal surface. If the spring is compressed 4.0 cm and released from rest, determine (a) the maximum speed of the object. Homework Equations F = -kx The...

so distance isn't included in the equation? and mass?

Homework Statement Water at the top of Niagara Falls has a temperature of 10.0degrees celsius. If it falls a distance of 50.0m and all of its potential energy goes into heating the water, calculate the temperature of the water at the bottom of the falls. Homework Equations W = change...

k. mass of the spool is not given so how can we solve the KEr??

potential energy = -mgh change in KEt + change in KEr + change in PE is that right? but what is v in KEt?