Heat and internal energy of water temperature

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Homework Help Overview

The problem involves calculating the temperature change of water as it falls from a height of 50.0 meters at Niagara Falls, starting from an initial temperature of 10.0 degrees Celsius. The context is centered around concepts of potential energy and heat transfer in thermodynamics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between potential energy and temperature change, questioning how to incorporate temperature into the energy equations. There is exploration of the relevant equations, including the potential energy formula and the heat transfer equation.

Discussion Status

Some participants have suggested a method to relate potential energy to heat absorbed by the water, while others are clarifying the role of mass and distance in the equations. There appears to be a productive direction towards formulating the relationship between the variables involved.

Contextual Notes

Participants are navigating the assumptions regarding the mass of the water and the relevance of distance in the equations, indicating a need for clarity on these points as they relate to the problem setup.

mizzy
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Homework Statement


Water at the top of Niagara Falls has a temperature of 10.0degrees celsius. If it falls a distance of 50.0m and all of its potential energy goes into heating the water, calculate the temperature of the water at the bottom of the falls.


Homework Equations



W = change in kinetic energy + change in potential energy

The Attempt at a Solution


i know there's potential energy on top and none at the bottom. There's not kinetic energy at the top and there is at the bottom. But how do i put temperature into this equation?
 
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The change in potential energy of the water = heat absorbed by water


You should know the equation Q=mcΔT
 
so distance isn't included in the equation? and mass?
 
mizzy said:
so distance isn't included in the equation? and mass?

The height is a distance and the mass will not really matter.
 
so, mgh = mc(T-Ti)

then solve for Tf?

therefore,

mgh = mc(Tf - Ti)
gh = cTf - cTi
gh + cTi = cTf
gh/c + Ti = Tf
 
Yes that should work.
 
Thanks
 

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