Recent content by Moomax

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    How do you take the Fourier transform of sin(t)/t using Parseval's Theorem?

    I checked on my transform table and looked around online a little and didn't see any transform that equals sin(w)/w. If there was i'd use the f(w) <-> F(t) rule and then it could work for me. Does that transform exist?
  2. M

    How do you take the Fourier transform of sin(t)/t using Parseval's Theorem?

    Homework Statement Evaluate INT(|X(t)|^2) dt using parsevals theorem where x(t) = (sin(t)cos(10t))/(pi*t) Homework Equations parsevals theorem: int(|f(t)|^2 dt = (1/2*pi)INT(|F(W)|^2 dw The Attempt at a Solution So I've tried several attempts at this problem and this is...
  3. M

    Help with Fourier Transform integration

    hhmmm so I did some reading on the residue theorem but am not really sure how to apply it if for instance the integral was t^2+4 instead of t^2+1 on the bottom. So in other words, another integral of interest would be: INT(-inf to inf) of exp(-jwt)/(t^2+4) dt. I'm guessing to solve this new...
  4. M

    Help with Fourier Transform integration

    Homework Statement Find the Fourier transform of f(t) = 1 / (t^2 +1) Homework Equations F(w) = Integral f(t) * e^-jwt dt The Attempt at a Solution Hi guys, so I've been having problems trying to solve Fourier transforms. It seems that slapping the e^-jwt makes it hard to...
  5. M

    Linear Algerba - Finding linearly independent vectors

    HallsofIvy is on the right track with what I mean. But I am still a little bit confused about the actual proceedure. Like what made you simplify the equations the way you did? When I was playing around with them trying to simpify it never occurred to me to set them equal the way you did...
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    Linear Algerba - Finding linearly independent vectors

    Hi guys, I am solving a problem in the form: (ATx=0 where A is a matrix of known numbers and I am solving for x. After performing reduction and multiplying ATx, I am left with the following equations: -X1 + X4 - X5 = 0 -X2 + X4 = 0 -X3 + X4 -X5 + 28X6 = 0 From these equations, I...
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