Recent content by mooney82

  1. M

    Work done by a constant force problem

    I got it to work out. You tha man Al!
  2. M

    Work done by a constant force problem

    Would you then solve by substitution? I'm having a hard time because F seems to cancel out.
  3. M

    Work done by a constant force problem

    Well, I summed the x component forces: Fcos45 - friction = ma acceleration = 0 friction = uk(N) N equals mg so Fcos45 - uk(mg)=0 F = uk(mg)/cos45 F = 0.25*1.8*9.81/cos45
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    Work done by a constant force problem

    Homework Statement A 1.8kg block is moved at constant speed over a surface for which uk = 0.25. The displacement is 2 m. It is pushed with a force at 45 degrees below the horizontal. Find the work done by: (a) the force F; (b) friction; (c) gravity Homework Equations W=Fs cos (theta)...
  5. M

    Friction problem with hardly any variables given

    Ya, I think so. I'll try it tomorrow, thanks a lot!
  6. M

    Friction problem with hardly any variables given

    But without the mass you can't find out the acceleration due to gravity. Without the force you can't find the mass.
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    Friction problem with hardly any variables given

    Homework Statement The minimum stopping distance for a car from an initial 100km/h is 60 m on level ground. What is the stopping distance when it moves (a) down a 10 degree incline; (b) up a 10 degree incline? Assume the initial speed and the surface are unchanged. Homework Equations...
  8. M

    Solving the Kinetic Friction and Tension of Two Blocks

    Homework Statement Block A (M1-5 kg) is on a horizontal surface and block B (M2-2 kg)to the left resting on a 30 degree incline. the two are connected to each other by a mass-less rope over a massless pulley and are moving down hill (to the left) at constant velocity. a) Find the...
  9. M

    Finding the force of a person given mass.

    Ahhh I get it, you see the only example my professor gave in class was with an outside force pushing at an object, here there isn't any other force besides her weight, or mg pointing straight down! Thanks, my professor sucks at explaining things, thank you very much!
  10. M

    Finding the force of a person given mass.

    Ok, so does the force from the girl start parallel to the ground or the incline? I think that is where I might be getting it wrong. I've been setting it parallel to the ground.
  11. M

    Finding the force of a person given mass.

    But if i set the x-axis on the incline wouldn't the x component be the adjacent side?
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    Finding the force of a person given mass.

    So the weight is just m*g, which is 294.3 N? The x component of mg would be 294.3cos10?
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    Finding the force of a person given mass.

    Homework Statement A 30-kg child on roller skates starts up a 10 degree incline at 15 km/h. Assuming she does not propel herself how far up the incline does she travel before stopping? Ignore frictional losses. Homework Equations F=ma W=mg The Attempt at a Solution I can do...
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