Well, I summed the x component forces:
Fcos45 - friction = ma
acceleration = 0
friction = uk(N)
N equals mg
so
Fcos45 - uk(mg)=0
F = uk(mg)/cos45
F = 0.25*1.8*9.81/cos45
Homework Statement
A 1.8kg block is moved at constant speed over a surface for which uk = 0.25. The displacement is 2 m. It is pushed with a force at 45 degrees below the horizontal.
Find the work done by: (a) the force F; (b) friction; (c) gravity
Homework Equations
W=Fs cos (theta)...
Homework Statement
The minimum stopping distance for a car from an initial 100km/h is 60 m on level ground. What is the stopping distance when it moves (a) down a 10 degree incline; (b) up a 10 degree incline? Assume the initial speed and the surface are unchanged.
Homework Equations...
Homework Statement
Block A (M1-5 kg) is on a horizontal surface and block B (M2-2 kg)to the left resting on a 30 degree incline. the two are connected to each other by a mass-less rope over a massless pulley and are moving down hill (to the left) at constant velocity.
a) Find the...
Ahhh I get it, you see the only example my professor gave in class was with an outside force pushing at an object, here there isn't any other force besides her weight, or mg pointing straight down! Thanks, my professor sucks at explaining things, thank you very much!
Ok, so does the force from the girl start parallel to the ground or the incline? I think that is where I might be getting it wrong. I've been setting it parallel to the ground.
Homework Statement
A 30-kg child on roller skates starts up a 10 degree incline at 15 km/h. Assuming she does not propel herself how far up the incline does she travel before stopping? Ignore frictional losses.
Homework Equations
F=ma W=mg
The Attempt at a Solution
I can do...