why [Y,Px] = 0
[Y,Px] = YPx-PxY
PxY=
P_x Y f(x) = i \hbar \partial /\partial x Y f(x)
P_x Y f(x) = i \hbar Y \partial f/\partial x + i \hbar \partial Y/\partial x f(x)
YPx=
Y P_x f(x) = i \hbar Y \partial f/\partial x
[Y,Px] = YPx-PxY
= i \hbar Y \partial...