Recent content by naav

Hi...thanks... 1. so i guess there's a similar recurrence relation for a geometric sequence...?... 2. so then why have a recurrence relation when you can express the SAME sequence by a formula...?...

Hi...thanks... i was told that a recurrence relation expresses a term in the sequence with regards to other terms in the sequence...whereas the formulae for the arithmetic and geometric sequences don't... ...?...

Hi... 1. so can i say that a recurrence relation is a description of the operation(s) involved in a sequence...?... 2. is the formula for an arithmetic sequence, a recurrence relation...?... and is the formula for a geometric sequence, a recurrence relation...?...

thank you very much...

Hi...thank you very much... i said in my earlier post... and it was said that it should be... 1. isn't that the same thing... that vector PQ = the magnitude of [z(2) - z(1)]...?...

Hi...i was wondering if someone could confirm if what i have below is correct...thanks...sorry i can't present a diagram... z(1) = x + iy and z(2) = x(2) + iy(2) are represented by the vectors OP and OQ on an argand diagram...(O is the origin)...imagine the argand diagram...the upper left...

Hi...thank you for trying...

thank you... 1. why multiples of 2pi...isn't the period of the tan function pi...?... 2. how come arg(z) = arctan[(img(z))/(re(z))] doesn't work here for the four complex numbers mentioned in my last post...?...

Hi...thank you... i don't understand how to get arg(z) for the following... 1. z = 2i 2. z = 3 3. z = -3i 4. z = -5 for part 1, arg(z) = arctan(2/0)...but that's undefined so does that mean it will be at pi/2 which is also undefined..??.. for part 2, arg(z) = arctan...

Hi...thank you again... 1. why does the fact that they differ by 2pi mean that they are they same...isn't the tan function periodic for pi...?... 2. have i explained the following correctly...for the complex number z = -sqrt3 - i, arg(z) = arctan (1/sqrt3)... 1st quadrant = pi/6 which...

thank you... i've tried to think about it more...here's what I've come up with... 1. complex number 1 is in the first quadrant so arctan(1) is pi/4 and pi/4 is between -pi and pi...so we can accept it as arg(z)... 2. complex number 2 is in the second quadrant...for arctan(-1), we see...

thank you very much...i'm still trying to get my head round this... sorry, for question 3, i meant to say that theta was projected clockwise... 1. okay how do we know that 7pi/6 is the same as -5pi/6...?... 2. why the different projections of theta - i mean anti-clockwise for the first...

Hi... my notes show the solutions to four complex numbers showing how arg(z) is obtained...they also show an argand diagram showing theta...there's a couple of things i don't understand so i was hoping that someone could shed some light...thank you... (i) z = 1 + i (ii) z = -1 + i...

Hi...sorry, i was meaning the first derivative - dy/dx... dy/dx = (dy/dt)/(dx/dt)

Hi...thank you... i got dx/dy = (dy/dt)/(dx/dt)... according to the answer I've got that bit right...