Recent content by nadeemo

from my integration by parts for <x^2> i get (L^2)/3 when accoring to that equation i should be gettin L^2[(n^2)(pi^2) - 6] / [12(n^2)(pi^2)] a = L, but you hafta multiply it by 2/L, since the wavefunction is sqrt(2/L) sin(nxpi/L)

<x> doesn't equal <p> in my textbook they show that, <x> = L/2 and <p> = 0.. and that integral doesn't really relate because x^n sin x...when i have (x^n)(sin^2 x)

so this pic basically solves my problem its just that... i wouldn't know how to integrate to get that in the first place and <x>^2 = L^2 / 4...and i can't incorporate that.. because well sqrt( <x^2> * (delta p)^2) = the answer that they want but i need (delta x)^2(delta p)^2 (delta...

<x^2> = 2/L integral (x^2)sin^2 (nxpi/L) dx = 2/L[x^2(x/2 - (L / 4npi)sin (2nxpi/L)) - integral x sin^2 (nxpi/L)] from 0 to L = 2/L[x^2(x/2 - (L / 4npi)sin (2nxpi/L)) - x(x/2 - (L/4npi)sin (2nxpi/L)) - integral of sin^2 (nxpi/L)] from 0 to L =2/L[x^2(x/2 - (L / 4npi)sin (2nxpi/L)) - x(x/2 -...

<x^2> = integral of (x^2)(psi^2) = 2/ L integral (x^2)sin^2(nxpi/L) dx integrate by parts from zero to L andd <x^2> = L^2 - L + 1 <p^2> = integral (conjugate psi)(momentum operator)^2(psi)dx <p^2> = -h/Lpi integral (conjugate psi)(d^2 psi/ dx^2)dx after taking derivative and the...

Homework Statement The analytical expression of \Deltax\Deltap for a particle in a box is: \Deltax\Deltap = h/2pi\sqrt{(n\pi)^{2} - 6} / \sqrt{12} for any quantum number, n Homework Equations (\Deltax)^{2} = <x^{2}> - <x>^{2} and (\Deltap)^{2} = <p^{2}> - <p>^{2} \Psi =...

thanks a bunch =)

so take the derivative of |psi*cojugate(psi)| and set it to 0? the conjugate would be A[x+1)^2 +1] ?

that gives you expected value of the particles position <x>, which is the next question, i need to find the most likely position of the particle... is there another way to do this?

Homework Statement Find the most likely position of the particle. Homework Equations \Psi = A[(x+1)^{2} - 1)] between x = 0 and x = 1 \Psi = 0 anywhere else The Attempt at a Solution I found A to equal \sqrt{15 / 38}... but I am not sure how to do the rest of it

hv / Kt = x kt/hv = 1/x 3kt/hv = 3/x 3kt/h = 3v/ x ...i still don't understand where you get "x/3" from, please clarify

so how should i change u(v)dv to u(lambda)d(lambda) i found a relation so i just replace dv with negative d(lambda)?? and then integrate?

wont it be 3x/v ?? since we have hv / kt = x andd in this part we have 3h/kt...wont that equal 3x / v

x/3 = 1 - e^(-x) why is it 'x/3' ?, and not just x

Homework Statement Given Planck's Radiation Formula Find the frequency (Vmax) at which energy density is at a maximum. This requires simple calculus and numerical solution of a simple transcendental equation. You only need to find the answer to 3 significant digits. Homework Equations...