Recent content by naoufelabs

Thanks

Hi, I have a system equation that I know its solution, but I want the steps that I can solve it: x*y = 3 4x2 + 2y2 = 72 x=y = √3 Thank you.

Thank you all.

Please I want the steps to find it, because I'm stumbled in the last steps as follow: x*Ln(3)-y*Ln(2)=Ln(19) 3*Ln(y)-x*Ln(2)=Ln(19) x*Ln(3)-y*Ln(2) - 3*Ln(y)-x*Ln(2) = 0 x*Ln(3)+x*Ln(2) = y*Ln(2)+3*Ln(y) {each one equals Ln(19)} x*Ln(3)+x*Ln(2) = y*Ln(2)+3*Ln(y) = Ln(19) x*Ln(6) =...

Hi everybody, Please I want to Solve the system: 3x-2y=19 y3-2x=19 x,y real number! Thank you !

Thank you very much Mr. Kurt Lewin

Hello all, Please I want to know the steps to find the integral primitive of this function: ∫1/[(x2)*(x+1)*(x-2)] dx. I know the result : 1/4 ln(x) - 1/3 ln(x+1) + 1/12 ln(x-2) + 1/2x The steps for normal function like 1/[x*(x+1)*(x-2)] were like : a/x + b/x+1 + c/x-2. My problem is...

Thanks

I ask about linear function.

Hi everyone, Please I have a problem to find a slope (Tangent line) of any linear function without using (x2-x1; y2-y1). What I want is a function that can be applied in any position of any type of function, example: x2, 3x3+sin(x), ln(x)+x3, and so one. (Like as in this web page "Java...

Thanks for all

I tested with Maple e^ln(a)*ln(b), then the result is a^ln(b). so I tested with 2 different numbers, example: 3^ln(2) = 2^ln(3) ==> Gives the same result. So I found that the e^ln(a)*ln(b) is commutative.

Sorry, I mean to achieve to result that a*b = b*a, and a*e=a. But I'm stuck on. Thanks

Please I have a problem with natural log for group set as follow:a*b=eln(a)*ln(b) 1- Show that the group law * is associative and commutative 2- Show that the group law * accept an element e (Identity element) Thank you !

Hello, thank you for your reply. I have found a solution : m2+1 \equiv 0[5] m2 \equiv -1[5] m2 \equiv 4[5] m \equiv \pm2[5] m \equiv 2,3[5] therefore : m= {2+5n ; 3+5n} for any integer n\geq0