Hello all, Please I want to know the steps to find the integral primitive of this function: ∫1/[(x2)*(x+1)*(x-2)] dx. I know the result : 1/4 ln(x) - 1/3 ln(x+1) + 1/12 ln(x-2) + 1/2x The steps for normal function like 1/[x*(x+1)*(x-2)] were like : a/x + b/x+1 + c/x-2. My problem is that I'm confused about (x2), I see at the end like a derivative of x2. Also if we have x3, I mean (∫1/[(x3)*(x+1)*(x-2)] dx.) we will have like a + b + c + d + e. ==> -3/8 ln(x) +1/4x2 + 1/3 ln(x+1) + 1/24 ln(x-2) - 1/4x Thank you for any help about this primitive.