- #1
naoufelabs
- 17
- 0
Hello all,
Please I want to know the steps to find the integral primitive of this function:
∫1/[(x2)*(x+1)*(x-2)] dx.
I know the result : 1/4 ln(x) - 1/3 ln(x+1) + 1/12 ln(x-2) + 1/2x
The steps for normal function like 1/[x*(x+1)*(x-2)] were like : a/x + b/x+1 + c/x-2.
My problem is that I'm confused about (x2), I see at the end like a derivative of x2.
Also if we have x3, I mean (∫1/[(x3)*(x+1)*(x-2)] dx.) we will have like a + b + c + d + e. ==>
-3/8 ln(x) +1/4x2 + 1/3 ln(x+1) + 1/24 ln(x-2) - 1/4x
Thank you for any help about this primitive.
Please I want to know the steps to find the integral primitive of this function:
∫1/[(x2)*(x+1)*(x-2)] dx.
I know the result : 1/4 ln(x) - 1/3 ln(x+1) + 1/12 ln(x-2) + 1/2x
The steps for normal function like 1/[x*(x+1)*(x-2)] were like : a/x + b/x+1 + c/x-2.
My problem is that I'm confused about (x2), I see at the end like a derivative of x2.
Also if we have x3, I mean (∫1/[(x3)*(x+1)*(x-2)] dx.) we will have like a + b + c + d + e. ==>
-3/8 ln(x) +1/4x2 + 1/3 ln(x+1) + 1/24 ln(x-2) - 1/4x
Thank you for any help about this primitive.
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