Recent content by Nicki

Ahhhh thank you! my mistake was in the calculation for the loop! i left the 4pi in place when using u/4pi hahaah that was dumb. but thank you, i got the right answer. it's 9.20 uT! :)

thats where I'm confused. shouldn't i use B = (uI)/(2 pi r) ? 4pi x 10^-7 x 1.6A / 2 pi x .144m ? this gives me 2.22 uT which when added to the 8.77 is out the the correct range

Homework Statement A conductor consists of a circular loop of radius R = 14.4 cm and two long, straight sections as shown in the figure. The wire lies in the plane of the paper and carries a current I = 1.60 A. Find the magnetic field at the center of the loop. Homework Equations...

Homework Statement Mass 1 (2.77 kg) moves with an initial velocity (1i - 1j) and mass 2 (1 kg) starts at rest. After the collision, M2 moves with a velocity of (2i - 3j). What is the final velocity of m1?Homework Equations Since they don't stick together, KE and linear momentum are conserved...

Unfortunately this is how we're expected to solve these for the time being I also realized I was missing KE for one of the masses,so now... I believe that dE = dE1 + dE2 and E1 = dU = mgHf - mGHi and dK = m/2 (vf^2 - vi^2) and E2 = dU = 0 and that dK = m/2 (vf^2 - vfi^2) also friction =...

Homework Statement "Consider the following arrangement of masses. Mass 1 is connected to mass 2 by a very light string and moves over a frictionless pulley so that both masses move with the same speed and move the same distances (m2 to the right and m1 down). Assume m1 = 15 kg, m2 = 15 kg and...