"Consider the following arrangement of masses. Mass 1 is connected to mass 2 by a very light string and moves over a frictionless pulley so that both masses move with the same speed and move the same distances (m2 to the right and m1 down).
Assume m1 = 15 kg, m2 = 15 kg and the coef. of kinetic friction is 0.73. The masses start with an initial velocity of 1.00 m/s. What is their speed after moving 0.0100 m?"
dE = E1 + E2 = dU1 + dK1 + dU2 + dK2
E1 = dU1 + dK1 (0) = m*g*dH
E2 = dU2 (0) + dK2 = m/2 * (vxf^2 - vxi^2) - friction?????
Friction = - 0.73 * mg * d
The Attempt at a Solution
This is where I'm getting stuck.
So do I set
m*g*dH = m/2 * (vxf^2 - vxi^2) - friction
and solve for vf through this equation?
or do I use m/2 * (vxf^2 - vxi^2) - m*g*dH = - friction?
I'm just not sure how to set up the final equation in order to solve for velocity.