Recent content by Nightrider55

Yea I don't know why he did it either. Can any else find a reason for it?

My teacher calculated 7.78 x 10^7 m. The difference is our calculations of the period. He did 5 x 12 x 3600 for the period while I did (24 x 60 x 60)/5. I don't understand where he came up with 12. Could someone help me see where my teacher or I made a mistake.

QUESTION: Suppose we want a satellite to revolve around the Earth 5 times a day. What should the radius of its orbit be? (Neglect the presence of the moon.) WORK: Found the number of second in 24 hours and divided it by 5 to get the period. Then rearranged the gravitational equation...

I talked to my teacher about it and he came to the same answer when he did it. I did show answer on the website and they calculated 8.8 cm. I don't know how they got that :confused: He sent an e-mail to the website tech support to notify them of the error. Thanks for the help!

It wants it in cm. I don't get why it says I am wrong.

Homework Statement Fred (mass 60.0kg) is running with the football at a speed of 6.0m/s when he is met head-on by Brutus (mass 120kg), who is moving at 4.0m/s. Brutus grabs Fred in a tight grip, and they fall to the ground. How far do they slide? Part A The coefficient of kinetic friction...

I am in calculus physics and I talked to my teacher and he didn't realize that he assigned such an easy problem :smile: I was aware that F = dp/dt before you told me but I didn't use it because I thought I was missing something because it seemed too simple of a problem considering it was...

so then it would be F=12t. That seems a little too easy. When they say Px would I also have to find Py in order to find the mag of P?

Homework Statement A particle of mass m is at rest at t=0. Its momentum for t>0 is given by Px=6t^2 kg m/s, where t is in s. Find an expression for Fx(t), the force exerted on the particle as a function of time. Homework Equations Px=MVx The Attempt at a Solution The question...

Yea I think I am doing it right, after I integrate it I get 12.73 then you say times that by the mass, so 12.73 x .42kg= 5.35. That should be right, could someone double check.

It keeps on saying my answer is wrong. What am I missing?

Homework Statement Force F_x =(10N){sin({(2pi(t))/4.0s) (where t in (m/s) is exerted on a 420 g particle during the interval 0 less than or equal to T is less than or equal to 2 seconds. If the particle starts at rest what is its speed at t=2 seconds? Homework Equations Jx= area under...

Homework Statement A popular pastime is to see who can push an object closest to the edge of a table without its going off. You push the 100 g object and release it 2.20 m from the table edge. Unfortunately, you push a little too hard. The object slides across, sails off the edge, falls...

Homework Statement what value of Fmax gives an impulse of 5.6 N\s? Picture of graph below http://session.masteringphysics.com/problemAsset/1070437/6/09.EX05.jpg Homework Equations Jx=Integral from t initial to t final of Fx(t)dt ^px=Jx The Attempt at a Solution I started...

I get 14.8 m/s^2 for the centripetal acceleration after using a=V^2/r then normal force is m times that which is 14.8 x .01 kg= .148044 N. Then friction is .8 times that which is .1184 N, for the Fsmax. Then Fs is calculated by m x g which is .098 N right? So this is below the max so the ball...