- #1

Nightrider55

- 18

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## Homework Statement

A popular pastime is to see who can push an object closest to the edge of a table without its going off. You push the 100 g object and release it 2.20 m from the table edge. Unfortunately, you push a little too hard. The object slides across, sails off the edge, falls 0.500 m to the floor, and lands 25.0 cm from the edge of the table.

If the coefficient of kinetic friction is 0.300, what was the object's speed as you released it?

## Homework Equations

y = (1/2)*g*t^2 therefore t = (2*y/g)^(1/2)

x = v2*t therefore x = v2*(2*y/g)^(1/2)

## The Attempt at a Solution

I worked everything out and I got 3.60 m/s for the speed when released but my online homework program says "Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures." I checked my work and I am not sure where I went wrong.

Here are the values I got

V2=.7836 m/s velocity when it leaves the table

T(3-2) time it takes to hit the ground once leaving the table=.319 sec

A0=-2.94m/s^2

V0=3.5966

To find V0 I used X1=(-Vox^2)/(2Ax) then solved for Vox any insight as to where I went wrong?