Recent content by Noreturn

1. The problem statement, all variables andgiven/known data Know how to find energy levels in infinite wells Homework Equations Good Question Is it: n^2h^2/8mL^2 3. The Attempt at a Solution So I am taking a test later today, and it was brought to my attention "know how to find energy levels...

Oh perfect, thank you I don't know how I didn't catch that.

So where did I do the math wrong?

OH didn't even notice that it's a weird unit on the .728. So .01 means it's going 1% the speed of light.

Homework Statement https://imgur.com/a/9UhMA Homework Equations Wavelength = planks constant/ mass*velocity The Attempt at a Solution (6.626*10^-34)/((9.11*10^-31)(.01*10^8)) = .728nm which is an option but they have .243nm as the answer and I don't know where I did it wrong or what I...

So Muliplying 1.66*10^-27 and 58.93 converts mass number of Cobalt from amu to kg.The Initial should be bigger. Just realized I may have had it right but I forgot to convert the kg to g. So my answer should have been 6.28ug

4*10^9 Bq =.132yr^-1*N or 4*10^9Bq = 4.18291693 × 10-9 Bq * N N= 9.56*10^17 9.56*19^17/e^(.132*3) = 6.43*10^17 (6.43*10^17)(1.66*10^-27)(58.93) =6.28*10^-8kg or 6.3ug

Do I need to divide by Avogadro constant?

I was not able to figure this out. Any help on where I went wrong is appreciated. So I'm guessing I did the -.1322 wrong based on what you guys have mentioned.

Oh! So: 4402 * (10^(-18)) kg = 4.40200 × 10-6 micrograms BUT bequerel is s^-1 @ 10^-6 so answer is 4.4micrograms?

Didn't we do that at the bottom of the image?

Homework Statement http://d2vlcm61l7u1fs.cloudfront.net/media%2Ff62%2Ff62b6919-e60f-405b-81fb-2323ceeb03ee%2FphpsL4bVl.png Homework Equations So I need that in micrograms tho. So 4402*10^-18/1000=4.4*10^-18kg. or 4.4*10^-12 micrograms that stills say it's wrong tho.

No sorry, so the anwser I got was 1.41 hbar. So I ended up getting sqrt(3(4))hbar sqrt(12) or 3.46 h bar So sorry guess 1.41 was wrong. However even with 3.56 or 3.6*10^-34 J*s was still wrong

Homework Statement A hydrogen atom is in the 7f state. What is the magnitude of its orbital angular momentum? Homework Equations L=sqrt(L(L+1)hbar The Attempt at a Solution L= Sqrt(3(3+1)Hbar) 1.41hbar (we want J*S) 1.41*1.054*10^-34 1.47*10^-34J*S

f=((1.55-1)((1/25)+(1/40)))^-1 f= ( (.55) (.065) )^-1 f= 28cm So I did figure out 2: s= ((1/10)+(1/16))^-1 Then the answer is negative on part 2 why? Then on both of them we have to end up adding instead of subtracting why is that?