Recent content by nova-ex

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    Find charge due to two particles

    I don't see anything wrong with it. Does anyone else see anything wrong with it?
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    Find charge due to two particles

    I would? because of the fact that there is no net force along the x axis. Hence all x components of the force must cancel out to equal 0. Do you not get the right answer by doing that?
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    Mag of impulse required to change speed question.

    Considering how high the speed of the particle is, I wonder if you have to consider relativistic momentum?
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    Why Refractive Index Varies with Wavelength of Light

    Homework Statement We learn from school that when we shine white light through a prism, dispersion occurs. This is because the light of varying wavelengths are refracted to a different extent due to how refractive index varies with the wavelength of light. So why does refractive index vary...
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    Speakers & sound waves

    You know, the simplest way to do this question is to make use of the young's double slit experiment equations? This is effectively the same thing, only the waves are sound waves and the screen is the person.
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    A real life problem, just for fun

    Hm. I'm not sure. But can I hazard a guess? There's a change in the depth of the water?
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    Simple conceptual question - rolling object question:

    Frankly, I have no idea which r to use. But What I would do is I would try and derive it. F = ma Torque = Moment of inertia x Angular Acceleration Now moment of inertia can be calculated using parallel axis theorem. After which you can find Torque. Angular acceleration can be calculated...
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    About work done

    Work done by a force must be moved through a distance. Yes this is true. However, you must keep in mind the fact that we are not considering work done ON the wall. We are considering work done ON the egg. The egg does moves, by a very minimal amount where the deceleration occurs.
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    Forces, action and reaction pairs

    Hi, Your method, including the kN portion, looks correct (Assuming you didn't make any computation errors). However, you may want to use another formula (also derived from these two) which would allow you to skip a step. (Vf)^2 = (Vi)^2 + 2aX This would save you having to compute time.
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    Time is all you need

    Hi. Considering the fact that the maximum height was not given, I do not think it is a good idea to exploit the symmetry of the situation. What do you think?
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    Electric Potential of two charges

    For that matter, I don't think you can let V = 0 because V is a scalar. I think we should set E (electric field strength) be zero and solve for x. However, when I do this I do not get the answer.
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    Electric Potential of two charges

    Hi. Actually, I think it's supposed to be (x+5). (this is wrong) No, it's (x-5) same idea as transformation on graphs I think. I'm sorry.
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    Electric Potential of two charges

    yes, that is what i meant.
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    Electric Potential of two charges

    Hi there I'm not sure if i'm right. I think the easiest way is to use your gut feel. That is it must be nearer to -2q than 3q since further away from 3q, the effect of the 3q charge would be less. Your approach looks right to me. But you must keep in mind that when you sub V = 0 in, you...
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    Impulse and Momentum of a puck

    Why is it a trick question? I would have thought what would happen is the tangential velocity would be maintained while radius would vary such that centripetal acceleration would equal to the gravitational force acting on the 100g weight left?