Recent content by Ockonal

There is car, that has motor with power P. From power I can calculate motor work per time: A = P*\Delta t P - power, A-work, \Delta t - time interval. \Delta t and P are known (calculations are performing by discrete time steps). Now, I want to calculate force F, that will produce car's...

Ok, nevermind. Solved it, thanks.

Homework Statement What work needs to be done to change body speed with mass 6×10⁴ kg from 2 m/s to 60 m/s? Homework Equations A = mgh A = FS A = mv²/2 The Attempt at a Solution A₁ = mV₁² / 2 A₂ = mV₂² / 2 A_res = A₂ - A₁; A_res = m/2 × (V₁² - V₂²) A_res = 3×10⁴ × (4 -...

Sorry, I can't understand from where did you get GM/R² in g' = G(M/100) _______ R/4

Didn't understand right, maybe: g_moon = G × ( M_earth / 25 × R_earth² ) g_earth = G × ( M_earth / R_earth² ) g_moon / g_earth = M_eath × R_earth² ----------------------- = M_earth × 25 × R_earth² 1/25

As I understand: D/4 = Moon's diametr, so: R/4 + R/4 = D/4 So radius is smaller in 4 times?

D_moon = 1/4 D_Earth R_moon = (1/4 D_Earth)/2 I'm confused :(

so: g_moon / g_earth = M_moon × R_earth² ------------------- M_earth × R_moon² Now I'm passing data instead of *_moon: (M_earth/100) × R_earth² ---------------------- M_earth × (D_earth / 4) How to make it easier? ----- I did this: M_earth × R_earth²...

so: g_moon / g_earth = M_moon × R_earth² ------------------- M_earth × R_moon² Now I'm passing data instead of *_moon: (M_earth/100) × R_earth² ---------------------- M_earth × (D_earth / 4) How to make it easier?

Homework Statement Mass of the Moon is nearly less in 100 times than Earth's, and the diametr is less in 4 times. Find the acceleration of free falling at the Moon. Homework Equations F = G×((M×m)/R²) g = 9.8N The Attempt at a Solution M_moon = M_earth / 100 D_moon = D_earth / 4...

Homework Statement A balloon which has weight 10.8 kN fall down with acceleration 1 m/s². What mass we have to pull of from balloon to make it(ballon) rise up with same acceleration. Homework Equations P = m×g P = m(g ± a) F =m×a P = 10.8 kN = 10.8×10³ N a = 1 m/s² g = 10 m/s² m₀ -...

Homework Statement There is inclined, smooth plane whish is sloped with angle 30 degrees. Some objects moves on it. The attraction power is 17 Newtons. Find the force which gives acceleration for the body. Homework Equations F = m×a; F_attraction = m×g; L = 30⁰; F_friction = u×N...

Thanks all.

Oh, if I understand you right: 0 = F - kN; 0 = N - mg; N = mg; 0 = F - kmg 0 = 2 - 0.02×k×10 k = 10; P = m×g; P = 10×10 = 100 (Newtons) And that is answer. Thanks, but did I understand right, there there woudnlt' be moving?

But this way there shouldn't be any moving, should it?