Recent content by ohlala191785

  1. O

    Prove function is continuous, multivariable

    Problem: If c is in Vn, show that the function f given by f(x) = c.x (c dot x, where both c and x are vectors) is continuous on ℝn. How do I go about proving this? I'm not sure if c is supposed to be a constant or a constant vector, but since it is bolded in the book I am assuming it is a...
  2. O

    Description of surface, vector calculus

    Oh OK. Thank you for your help.
  3. O

    Description of surface, vector calculus

    So the description of the surface just an ellipse? If you project the circle onto the slanted plane, it should look like an ellipse.
  4. O

    Description of surface, vector calculus

    Homework Statement Consider the surface parameterized by (v cos(u), v sin(u), 45 v cos(u)), where u and v both vary from 0 to 2∏.Homework Equations (v cos(u), v sin(u), 45 v cos(u)) I think this is supposed to be a vector function? As in r(u,v) = <v cos(u), v sin(u), 45 v cos(u)>.The Attempt at...
  5. O

    Cylindrical coordinates, finding volume of solid

    Homework Statement Find the volume of the solid that the cylinder r = acosθ cuts out of the sphere of radius a centered at the origin.Homework Equations Cylindrical coordinates: x = rcosθ, y = rsinθ, z=z, r2 = x2+y2, tanθ = y/xThe Attempt at a Solution So I know that the equation for the sphere...
  6. O

    Double Integrals, Rectangular Region

    Alright then. Thank you!
  7. O

    Double Integrals, Rectangular Region

    So since the min of sin(pi*x) is 0 and max is sqrt(2)/2, and it's the same for cos(pi*x), then the min of their product is 0 and max is 0.5. Is that correct?
  8. O

    Double Integrals, Rectangular Region

    k=0.5 I graphed sin∏xcos∏y on Mathematica and saw that for x in [0,1/4] and y in [1/4,1/2], z is between 0 and 0.5. And solving for k=0.5 agrees with the graph. I'm also wondering if you can know that z is from [0,0.5] without graphing it on a computer or something?
  9. O

    Double Integrals, Rectangular Region

    Wait hold on is it ∫∫kdA = 1/32, for R = [0,1/4]x[1/4,1/2]? So k(1/4-0)(1/2-1/4)=1/32.
  10. O

    Double Integrals, Rectangular Region

    Ohh is it (1/32)(1/4-0)(1/2-1/4)?
  11. O

    Double Integrals, Rectangular Region

    k=1/32. Sorry, I still don't know how to proceed.
  12. O

    Double Integrals, Rectangular Region

    Homework Statement Using ∫∫kdA = k(b-a)(d-c), where f is a constant function f(x,y) = k and R = [a,b]x[c,d], show that 0 ≤ ∫∫sin∏xcos∏ydA ≤ 1/32, where R = [0,1/4]x[1/4,1/2]. Homework Equations ∫∫kdA = k(b-a)(d-c) 0 ≤ ∫∫sin∏xcos∏ydA ≤ 1/32 The Attempt at a Solution I tried to...
  13. O

    Multiple integrals: Find the volume bounded by the following surfaces

    So z is from 0 to 10x^2 + 4y^2, y from 14 to 2x, but what would the limit of x be? The lower bound is 0, how would I find the higher one? Also is the integrand just 1? Thanks!
Back
Top