Recent content by Okazaki

Oh, λν = c. Literally, the one formula not in my book.

Homework Statement The half wavelength "dipole" loop roof television antenna is most sensitive to electromagnetic waves with a wavelength twice the width of the antenna. The frequency of the waves for TV channel 10 is 200 MHz. If you want to optimize the TV reception for channel 10, how wide...

Oh yes...it appears I am mixing up threads. Sorry about that. :/

No. The original equation (I had a typo when I transcribed it from my homework) it was - phi. So the second required wave equation is: 10 cos (π/2)(0.0050x + 8.0t - ϕ). How do you find phi?

So, I attempted to get some help from my friend. She screwed up a bit during the process (basically, she didn't alter the direction in which the wave was moving, so basically added the exact same equation to the original one) but: y(x,t) = 10 cos (π/2)(0.0050x - 8.0t - 0.57) I think I messed up...

The omega*t determines which way it's moving, right? That's why waves traveling in the negative direction have the equation ##A \sin(k x +\omega t +\phi)## right?

That's what I'm struggling with. I don't know how to find it when there's a phase constant.

Homework Statement The equation of a transverse wave traveling in a string is given by y(x,t) = 10 cos (π/2)(0.0050x - 8.0t + 0.57), in which x and y are expressed in centimeters and t in seconds. Write down the equation of a wave which, when added to the given one, would produce standing...

Homework Statement A string vibrates according to the equation y(x,t) = 2.0*sin (0.16x)cos (750t) , where x and y are in centimeters and t is in seconds. (a) What are the amplitude and velocity of the component waves whose superposition give rise to this vibration? (b) What is the distance...

No. I think my friend was trying to explain to me that the reason I could just use Potential Energy in the equation was because the block/bullet combo is at it's maximum compression where I'm evaluating it (so, no Kinetic energy). No? I honestly don't know.

Yeah, when I did the problems out, I kept my significant digits (I screwed up the first few times I worked with lbs, and so when I do my work out, I usually keep it as lbs/32.2 ft/s2. I just wanted a number here, which ended up losing a lot of precision. I'll keep that in mind in later...

Mass of the bullet+block combo.

Well, if it's at h', then the Vi-x will be √(2g(H-h')) and you can work backwards from there.

Wait, I see the issue. In my notes, I think I had a square root sign. It just never made it onto paper.

v = √(2gh) was what I had to prove in the previous problem.