What is the Width of the Antenna for Optimizing TV Reception on Channel 10?

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Homework Help Overview

The discussion revolves around determining the width of a dipole antenna for optimizing TV reception on channel 10, which operates at a frequency of 200 MHz. The relationship between the antenna width and the wavelength of the signal is central to the problem.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between frequency and wavelength, questioning how to derive the antenna width from the given frequency. Some express frustration with the complexity of the equations and the number of unknowns involved.

Discussion Status

There is an ongoing exploration of the wavelength corresponding to the 200 MHz signal, with some participants suggesting that the antenna width should be half of this wavelength. Multiple interpretations of the problem are being discussed, but no consensus has been reached on how to proceed with the calculations.

Contextual Notes

Some participants note the absence of certain formulas in their resources, which may be contributing to their difficulties in solving the problem. The emotional tone indicates a sense of frustration with the material.

Okazaki
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Homework Statement


The half wavelength "dipole" loop roof television antenna is most sensitive to electromagnetic waves with a wavelength twice the width of the antenna. The frequency of the waves for TV channel 10 is 200 MHz. If you want to optimize the TV reception for channel 10, how wide would you construct this antenna?

Homework Equations


f = v/λ = ω/(2π) = n (v/2L)
v = ω/k = λ/T = λf

The Attempt at a Solution


No matter how hard I try, everything keeps cancelling out. I just can't do this problem!

ω = 2πf
T = 1/f
k = vω
v = 2Lω/(2πn)
= Lω/(πn)

But now, there are just too many unknowns. I don't even know where to begin to substitute. :/ I'm just so frustrated right now. Waves are killing me. I have like, three problems left in this homework assignment, and none of them make sense to me (so I can't skip this one and move on.)
 
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What's the wavelength of the 200 MHz signal?
Then it says the antenna width should be half the wavelength of the signal.
What could be simpler?
 
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rude man said:
What's the wavelength of the 200 MHz signal?
Then it says the antenna width should be half the wavelength of the signal.
What could be simpler?

Oh, λν = c.

Literally, the one formula not in my book.
 
Okazaki said:
Oh, λν = c.

Literally, the one formula not in my book.
C'mon, has to be! :smile:
 
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