Ok, so I've been passionately researching my latest novel idea as it takes place in an extremely far fetched future with long range interstellar travel and all that and the brink of controlled time modulation etc...
While doing this, I've been able to name every site, system, planet of...
Thank you so much guys, I was banging my head on my desk with that. The solution
y = \frac{(x+8)^{9}}{13} + (8^{5} - \frac{8^{13}}{13})(x+8)^{-4}
checked out.
I didn't think it'd matter... I get the same thing.
y = \frac{(x+8)^{9}}{13} + C_{1} | where C_{1} is just another arbitrary constant that will satisfy the equation given the initial conditions. I get the same constant regardless...
8 = \frac{8^{9}}{13} + C_{1}
C_{1} = 8 -...
Homework Statement
Solve the initial value problem:
y'+\frac{4y}{x+8}=(x+8)^{8} , y(0)=8.
The differential equation is linear.
Homework Equations
N/A
The Attempt at a Solution
I can see that the equation is in the form y' +P(x)*y = Q(x) so I'm like "easy, let me get an...
Well the first step is just an algebra step, you have log (x) on both sides of the = sign, so the equation can be reduced. When that happens you are left with a log (of something) = log (of something else) when this happens you can sort of drop the log and just solve for x.
Hey there,
ok it looks like you have some exact same term on both sides to begin with, so those can just cancel out right? This leaves you with a log of something = a log of something else, that should simplify it down nice for ya.
Ugh... Sorry to waste your time. The limit is pi/2, all I had to do was take the limit and I was already done lol. For some reason I thought there would be no limit for the arctan and that was bothering me.
Been doing some calculus review to knock the rust off for this coming fall semester and I got stuck...
Homework Statement
From Stewart's book (Early Transcendentals: 6E): (7.8 pg517 #69)
Determine how large the number "a" has to be so that:
\int\stackrel{\infty}{a}\frac{1}{x^{2}+1}dx...
Although, my answer is wrong
Hmm, I just gave this a shot myself and got the same magnitude for the r vector, it looks correct to me...!
What did you get for the angle?
Hey Cyril, I think Mark pretty much covered everything but I wanted to chime in about coefficients as it sounds like you're just getting your pinky toe wet with Algebra.
The 0.06x from your first problem has two parts and you were correct in that they are multiplied together (the number and...