Recent content by Oxfordstudent

Ah, thanks, that makes it clear - ML can take values of 3, 2, 1, 0, -1, -2, -3, so L = 3 for ground state.

Why do they have to occupy orbitals with different values of l rather than just ml ? If they are d2 electrons, the value of l must be the same ? l = 1, 2 would have one electron in a p orbital, surely.

No, the enolization is the rate determining step in these reactions.

Forgot to attach.

Hi, I've been working through my lecture notes from last year and I encountered this example of Russel-Saunders term symbols. I'm confused by the value of L being given as 1 + 2 = 3. What I recalled was that L is defined for two electrons by the Clebsch-Gordan series L = l(1)+l(2), l(1) +...

This is only the case if the reaction is elementary: i.e. if there are no intermediate steps. In reality the kinetics of this reaction are complex, due to a multi-step mechanism: see http://www.docbrown.info/page15/mech47.gif.

Yes, that would be the case. I think I was just confused by ξ being an operator.

Sorry about copying that equation incorrectly - I think my brain must have given up on the formatting. The thing I don't understand is why 21 is zero for all ξ given that it is zero for the substitution Cs (s = 1, 2, 3...n). Dirac justifies it by saying that the expression is of degree n-1 in...

Hi everyone, I'm currently working my way through Dirac's Quantum Mechanics, and I found this proof really irritating. We're trying to demonstrate that any eigenket can be expressed as a sum of eigenkets of a real linear function \xi which satisfies the equation \varphi(\xi) =...