Recent content by p75213
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Is it possible to eliminate back EMF in a transformer and achieve free energy?
None of the above. The idea is to remove the back emf from the secondary to the primary. The result of doing this is to reduce, if not cancel, the increase in amperage draw from the source due to the load on the secondary. Effectively the source only has to supply enough current to maintain the...- p75213
- Post #9
- Forum: Electrical Engineering
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Is it possible to eliminate back EMF in a transformer and achieve free energy?
Surely if you only have to maintain the magnetizing current that creates the magnetic flux that has to be efficient.- p75213
- Post #5
- Forum: Electrical Engineering
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Is it possible to eliminate back EMF in a transformer and achieve free energy?
Well think of a capital 'E' turned on its side with a connecting piece across the top. The primary coil is wound on the center leg and the secondaries wound on the two end legs. This transformer would only work one way.- p75213
- Post #3
- Forum: Electrical Engineering
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Is it possible to eliminate back EMF in a transformer and achieve free energy?
I have been reading about mag-amps which gave me an idea for a more efficient transformer. So the core is in the shape of a square or rectangle with a center piece dividing it into two. The construction of the outer core is larger (less reluctance) than the middle leg (greater reluctance). The...- p75213
- Thread
- Transformer
- Replies: 12
- Forum: Electrical Engineering
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Calculating Peak Capacitor Voltage Across a Half-Wave Rectified AC
The charging path is what I am interested in. Your right - I don't understand the circuits operation.- p75213
- Post #6
- Forum: Electrical Engineering
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Calculating Peak Capacitor Voltage Across a Half-Wave Rectified AC
dVc/dt = VpSin(ωt)*1/RC*e-t/RC+(1-e-t/RC)*Vp*ω*Cos(ωt) Don't ask me to plug values into that or graph it. I've already tried and can't get anything to either calculate a result or graph it.- p75213
- Post #4
- Forum: Electrical Engineering
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Calculating Peak Capacitor Voltage Across a Half-Wave Rectified AC
Hi, I am trying to figure out the peak voltage across a capacitor when charged by 1/2 wave rectified AC. The formula for instantaneous voltage is : Vc=Vs(1-e-t/RC) where: Vc=Capacitor voltage, Vs=Source Voltage, t=time RC = the capacitor time constant So I thought I could integrate with...- p75213
- Thread
- Capacitor Voltage
- Replies: 6
- Forum: Electrical Engineering
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Capture Energy from Inductor to Power Load
This post is inspired by a lesson on the allaboutcircuits education website. In chapter 15 of Direct Current there is a heading "Inductors and Calculus" - https://www.allaboutcircuits.com/textbook/direct-current/chpt-15/inductors-and-calculus/ At the bottom of the topic there is a circuit...- p75213
- Thread
- capacitor energy inductor
- Replies: 1
- Forum: Electrical Engineering
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Graduate Plasma Multipactor by Gene Meeks: Self-Sustaining Power Device?
I have been reading a patent by Gene Meeks of a plasma multipactor. Meeks was the right hand man of Philo Farnsworth the "father of television" and worked with him on the 'fusor' - a small nuclear fusion device. Meeks's multipactor appears to be a self sustaining over unity power device...- p75213
- Thread
- plasma
- Replies: 2
- Forum: High Energy, Nuclear, Particle Physics
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The mean of the Probability Density Function
Thanks guys. I've done some more reading and investigation. Rather than the mean I prefer to think of it as "expected value".- p75213
- Post #4
- Forum: Calculus and Beyond Homework Help
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The mean of the Probability Density Function
Homework Statement The mean of a function is as follows: $${1 \over {a - b}}\int_b^a {f(x)\,dx} $$ So why is the mean of the PDF as follows: $$\int_{ - \infty }^\infty {xf(x)\,dx} $$ I thought it would have been this way: $$\lim \,b \to - \infty \,{1 \over { - b}}\int_b^0...- p75213
- Thread
- Density Density function Function Mean Probability Probability density Probability density function
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Ideal Transformers and Lenz Law
Hi, Can somebody answer this question? The induced magnetic field of the secondary coil opposes the magnetic field of the primary. Therefore there is a lower magnetic field on the primary - lower impedance and a lower voltage drop. This results in an increased primary current which will...- p75213
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- Law Lenz Lenz law Transformers
- Replies: 2
- Forum: Electrical Engineering
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2 Port Networks - Impedance Parameters
Thanks guys. I have learned a lot from this book in spite of the many errors.- p75213
- Post #4
- Forum: Engineering and Comp Sci Homework Help
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2 Port Networks - Impedance Parameters
Homework Statement see attached Homework Equations The Attempt at a Solution $$\eqalign{ & {V_1} = {Z_{11}}{I_1} + {Z_{12}}{I_2} \cr & {V_2} = {Z_{22}}{I_2} + {Z_{21}}{I_1} \cr & {\rm{ - - - - - - - - - - - - - - - - - - - - - - - - - - - }}...- p75213
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- Impedance Networks Parameters
- Replies: 3
- Forum: Engineering and Comp Sci Homework Help