I know how to solve this using Snell's law and geometry, but I thought of a different approach- using normal shift
Firstly here is a diagram for the geometry of the situation:
Now somehow, if we raise the image of P to a height of ##h## from the bottom, it will be right on the line of sight of...
oh I forgot to count the reflection at M1. so this is the mistake in my solution.
However if there were no constraints on the number of reflections, then would this be correct?
There is the figure provided.
I know how to approach this problem analytically, but before that I tried to use some logic-
Using mirror formula assuming the first reflection occurs at M1, we get that the first image is formed at a distance ##60 cm## from the pole of M1 to its left.
So, if this...
I think I have found my mistake.
In this charging equation, I had to substitute ##i_{s.s} ## as -E/(2R) and not just E/2R . (As the steady state current in the inductor is upward, as opposed to the initial current which is downward.) Have I identified my mistake correctly?(I'm getting the...
I think there is some misunderstanding here. My original question posted here was a part of a larger question, which is the one described above in the previous message.
okay let me post the larger part of the question here.
this was the original circuit. I am required to find the voltage across the inductor after S2 is closed at t=0+, given that initially S1 was closed for a long time, so as to establish an initial current ## i_0= E/R## through the inductor...
In this seemingly simple circuit, applying KCL, I get the current in the shorted branch as
## 3E/(2R) - 2E/(2R) = E/(2R) ## but some sources suggest that it is ##5E/ (2R) ##
which is right and why?
This is the diagram given for the problem.
Now I was able to identify, that the fact that the capacitance of a spherical capacitor, with one plate and the other at an infinite distance, is somehow to be used in this problem, i.e ##C= 4\pi\epsilon_0R ##
IF I can replace all the spherical...
I have another question:
If angular momentum is conserved, then it would be conserved in all directions. But in the horizontal direction, the initial angular momentum is zero, and the final angular momentum is non zero (## L_{aboutcm}## of the vertical disc).
Why is this? Am I right in the first...