Recent content by paperclip

I figured out what I was doing wrong- in my old calculator, I could just press, for example [10^x][5], but on this new calculator, you need to press [shift][log]. Still not sure what the difference is, but it does what I need it to do, so I'm happy now. Thanks for your help :)

If I try to do 1+ 10^3.9, for example, I just get 'syntax error'. Argh! Help?

Kobs= observed rate of reaction Kh is the concentration of [H+] Koh is the concentration of [OH-] ko is the constant. Rearrange... k=[H]+ko-[OH-] pH=pKa + log [unionized/ionized] where ionized= [OH-] and/or[H+] and ionized [H20] Hope this helps...

Homework Statement The rate of degradation of a drug D that is subject to hydrolysis is given by the first order equation rate=kobs (D) where Kobs= Kh (H+) + Ko= Koh (OH-) Derive an equation for the pH at the minimum (pH)min of the pH/rate profile. The Attempt at a...

Nobody? Ah, come on...sure it must be easy enough to just say 'yes, you got it right' or 'no way, you're way off the mark?'

I suppose I meant while the particles were still so close together that they were still more or less associated with one another, then they would still be 'mostly in the solid phase'. Brownian motion refers to particulate matter widely dispersed in the solvent, so that WOULD mean 'dispersED'...

Hi! I want to make sure I have the right handle on this. Fick's law relates to dispersING solids, whereas Einstein's law of diffusion indicates disperSED particles, Stoke's law illustrates sedimentation and D=kT/6πηNa=RT/6πηaN is the overall equation relating all of the above to...

Hi, I have here an alkyne reacting with C2H5NH2 in the presence of lithium and NH4Cl. Does the lithium catalyse the split of a proton from C2H5NH2 and also a Cl from the NH4Cl which then react with the alkyne across the triple bond?

1x10^12 which worked out gives a final answer of 3.9x10^16...closer, but still no cigar!

Thanks so much for the help, guys! You're helping this strange language to settle itself into my brain. Thanks for the pointers. Hmm, no new magical forces appear? I'll have to think about that one! No unicorns, then? Wait a minute though...Fc=Ff=m*v^2/r? so 1200x8^2/9? This gives me...

Dick, I put in a symbol there- mw^2r, not mr. It's possible that the symbol isn't showing up on your browser. Isn't friction plus tangential force the force opposing centripetal motion? As in, the tangential force is the horizontal force indicated in the question? I'm afraid the professor wasn't...

Hello all, I also have a calculus thread in the appropriate forum- I wanted to have a separate physics thread in order to make things a little tidier around here! A quickie: A 1,200kg car turns a corner at 8ms^-1 and travels along the arc of a circle radius 9m in the process. How large...

y=30sin 40= 19.28m y=vot+0.5at^2 -4=19.28t-.5(9.8)t^2 -9.8t^2+19.28t+8=0 (a) (b) (c) Use quadratic formula [- b +/- sqrt (b^2-4ac)] / 2a [-19.28 +/- sqrt (19.28^2-4 (-9.8)(8)]/2(-9.8)] and so on forth, until t is found to equal -0.3519 and 2.319. T must be...

Hey, thanks for the explanation...I understand it a bit better! I see from your title that you're all into physics, so can you tell me if I have the right end of the stick with this: Y=30 sin 40=19.28m X=30 cos 40=22.98 Displacement in the X-direction: x=Vot+ 0.5 at^2, a=o, so...

I figured out what the problem was- the function was to the power of x, not 2. It was from a lecture example. No wonder I couldn't get the right answer. Talk about wasting time! Another question for you to try and gently explain to my puny little brain: the whole P(t)=Poe^kt deal. See, the...