Recent content by parttime

a steel rod undergoes a streching force of 500n its crossectional area is 2cm^2 find the temp change that would elongate the rod by same amount i useyoungs modulus to get change in length so ym= (F/A)/(deltaX/h) so i solve for r (which is = to h from area of circle) and with a ym for steel...

i was able to get the h without a problem but i am having trouble getting v as I am not sure what i am comparing to solve for v

this is what i do and still don't get the right answer solve for v with pAv =125cm^3/16.3s with p= density of water A= area of stream at the faucet so v = v1 with v1 i solve for v2 with v2^2 = v1+ 2 a (xf- xi) having both velocitys i use A1v1=A2v2 and A2=pi * r^2 i to solve for r i also...

for 1 isn't w = mg which give you .6kg *9.8 = 5.88 founded up to 5.9 for 2 what i think is this not sure if you have the answers to checkif it is correct f = ma f= 60 * 9.8 + and - 3 m/s just a guess not sure

a stream of water in steady flow from a kitchen faucet. at the faucet the diameter of the stream is .96cm teh stream fill a 125cm^3 conaienr in 16.3s find teh diamiter if the stream 13cm below he opening if the faucet i know that A1V1 = A2V2 = constant so pi *.49^2 *V1= pi r^2 *V2 how do i get...

thanks for the help finally got it to give me the correct answer since i had it from the book just couldn't get it to come out . this is what i have sum forces x = t1 - uf*m1*g =m1 *a sum forces y =t2 +uf*m2*g*cos()-m2*g*sin() =m2*-a that i don't understand is why for the y the weight is...

so would it be t -sin30*m*g + ufcos30*m*g? also is the tension a and b both positve because the are going in the same direction or would tension b be negitive can't make sense of it

for the sum of forces along y sin 30 mg for the force of gravity i just can't get the tension not sure if it is just t or tcos30

there are two blocks on a trapizoid one on the top and one on the side with the slope a wire that goes throu a pully connects the two. determin the the acceleration of the two blocks. block one =m1 block two = m2 pully =m with radius r Ufriction =.36 what i have so far is sum of...

thanks i got it now

three identical thin rods each of length L and massM are welded perpendicluar to one another determine the monemt of inertia of the structure pink line is the axis of rotation. i think i need to use Icm= 1/12 ML^2 and I=1/3ML^2 but not sure which rod uses which formula

i have this problem i can't seem to get i think i am overthinking but just can't get it what is. this is a one dimensional motion with constant acceleration.what is the acceleration of a space capsule fired from a 220m long cannon with a launch speed of 10.97km/s