Homework Statement
What are the congruences between a square and itself?Homework Equations
none
The Attempt at a Solution
Let A, B, C, and D be the sides of the square and e, f, g and h the four right angles.
All four sides are congruent to themselves--same with the angles.
Side A is...
As someone who's interested in the history/ideas of mathematics I'm attracted towards the pure track but I'm also attracted to the job prospects of applied math.
Are my impressions wrong? Can one find employment with either concentration, or is the applied track superior in that regard?
Homework Statement
Prove that log2 of 5 is irrational.
Homework Equations
None.
The Attempt at a Solution
I just had a glimpse of the actual solution, but I'm wondering if mine would work too.
2^(a/b) = 5
square both sides...
2^(2a/b) =25
2 = 25^(b/2a)
(b/2a) = log25 of 2
b =...
I currently attend a community college.
For several semesters I did poorly--failed one class and dropped out of a fair amount, but then I turned things around and consistently received decent grades. The track I am currently on is "Business Administration"--in short, I plan to study...
These were my steps:
d/dx = (x^3)/2 -1/2x^3
You take out the one half and you get: (1/2)(X^3 - 1/x^3)
Now you square it, and you get: (1/4)(X^6 - 2 + 1/x^6)
It is this plus 1 that we take the square root of, so we incorpate the 1 by adding four to the product (balanced out by (1/4))...
Sometimes I guess it helps to reassess your assumptions...
I did indeed have the derivative wrong, which is why the integral was giving me such a hard time:redface: . But I solved it, so thanks for the help! :smile:
Homework Statement
Just started Calc II last month, it's been smooth so far but I've run into a bit of snag involving the application of integrals in the calculation of arc length.
The formula you use is the definite integral of (1+(d/dx)^2)^.5.
Often once you derive the d/dx and...