Recent content by PattyCake

but are you sure I did it right?

So I used Coulombs equation. F=kQQ/d^2 I knew that F=F+F So I just wrote the equation F=k/d^2(QQ+QQ) I plugged the constant in for k. converted 19cm to meters so it changed to .19m. Then plugged in ((-12)(2)+(2)(3)) but then I didn't change them to coulombs. So that through me off. So instead I...

How do you remove this from the feed?

I think I'm just confused because the book does it completely differently and my answer isn't the same. I think there Is error rounding. and I didn't initially understand the formula. The more I looked at it I had a urikea moment.

I think q1 is 12uc

1. Given that q=+12uc distance=19cm Find Magnitude and direction exerted on point q2. What happens to the force if the distance is tripled?q____________ q2 ____________q3 q1=+12 q2=-2.0q q3=+3.0q distances between point are equidistant.The Attempt at a Solution F=k Q Q/ d^2 F=F+F...

i know that k=1.0 x 10^4 x(final)=-0.15 x(initial)=0 work=1/2kx^2= -112.5 but i don't know how to find the velocity i tried using v^2=k/m (x^2) and received 13.69m/s

A 1.2 kg block is held against a spring of force constant 1.0 x 10^4 N/m, compressing it a distance of 0.15m. How fast is the block moving after it is released and the spring pushes it away?