What is the Velocity of a Block Released from a Compressed Spring?

AI Thread Summary
The discussion revolves around calculating the velocity of a 1.2 kg block released from a compressed spring with a force constant of 1.0 x 10^4 N/m, compressed by 0.15 m. The potential energy stored in the spring is calculated using the formula 1/2 k x^2, resulting in -112.5 J. The user attempts to find the velocity using the equation v^2 = k/m (x^2) and arrives at a speed of 13.69 m/s. Other participants confirm that the calculations are correct, indicating that the derived speed aligns with expected outcomes based on conservation of energy principles. The discussion emphasizes the importance of understanding energy conservation in determining the block's velocity.
PattyCake
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A 1.2 kg block is held against a spring of force constant 1.0 x 10^4 N/m, compressing it a distance of 0.15m. How fast is the block moving after it is released and the spring pushes it away?
 
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think about conservation of energy, and the potential energy stored in the spring before release
 
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i know that k=1.0 x 10^4
x(final)=-0.15
x(initial)=0
work=1/2kx^2= -112.5

but i don't know how to find the velocity

i tried using v^2=k/m (x^2)
and received 13.69m/s
 
Do you think that's wrong?
You solved for v. v is the velocity. well technically the speed here, but I'd assume that's what your teacher meant.
 
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Looks good, average force seems to satisfy.
 
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