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Deriving decomposition of transverse acceleration
Thank you. I'd tried the process of working backward by differentiating the textbook answer, but completely forgot the need to use the chain rule when doing so. I really appreciate the help.- philipfisher
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- Forum: Introductory Physics Homework Help
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Deriving decomposition of transverse acceleration
Homework Statement The question asks one to derive the acceleration vector, $$\vec{a} = [\frac{d^2r}{dt^2} - r(\frac{d\Theta}{dt})^2]\vec{u}_r + [\frac{1}{r}\frac{d}{dt}(r^2\frac{d\Theta }{dt})]\vec{u}_\Theta$$ from the velocity vector. $$\vec{v} = \vec{u}_r\frac{dr}{dt} +...- philipfisher
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- Acceleration Decomposition deriving Transverse
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- Forum: Introductory Physics Homework Help