Recent content by pocaracas

Hi, I've been dealing with a really mind buster, at least, for me. Here it is I_n(r,z)=\int_z^r\frac{p^n}{\sqrt{r^2-p^2}\sqrt{p^2-z^2}}\,dp where n is an integer and 0<z<r<1. Mathematica tells me that the result is zero, but I'd like to know how to get there. I've thought about...

no ideas? :(

thanks man!

I just noticed that T_n(x) = 2 x T_{n-1}(x) - T_{n-2}(x) is just the same as xT_n(x) = \frac{1}{2}(T_{n+1}(x) + T_{n-1}(x)) :(

I could, but I need to know how to add latex code here.

Now in LaTeX hope it's ok (the preview sucks): 1. Homework Statement given the integral I_n(r,z)= \int_z^r \frac{T_n(\frac{p}{z})T_n(\frac{p}{r})}{p \sqrt{r^2-p^2} \sqrt{p^2-z^2}} dp where T_n(x) is the chebyshev polynomial of the first kind: T_n(x) = 2 x T_{n-1}(x) - T_{n-2}(x) T_0(x)=1...