Recent content by pokerfan91

its clicked! right so i'll get my position vector and my parallel vector and because the vector is parallel and not acctuly on the line (however in the same direction) it needs to be that direction but to a diffrent scale (hence t) plus the position vector giving X=(-3,3,-9)t +(4,2,1) right so...

also how do i find the intersection? which parameters do i set as s and t the position vectors?

-3 3 -9

what exactly is incorect about the first one?

so for the first 2 parts would my answers be ok like this or would i have to arrange it differently X=t(4,2,1)+(-3,3,-9) X=t(2,1,1,)+(3,0,3)

that is what the dot product is ment to give me isn't it i just have no idea where to go after that to get the angle

ive got the formula down as angle=cos-1[(u.v)/(||U||||v||) with my u as 3,1,2 and v as -2,3,4 this gives me cos-1[(-6i+3j+8k)/root406) where do i go from here?

for the question n+1=X2n-2Xn+2 one of the roots is 1, now if i take 1.1 and put it in i get a negitive and if i take 0.9 i get a positive does this make is a saddle point? also F'(x)=0 what do the F'(x) values indicate? something about being smaller or larger than 1

i have an exam in a few days and am certain a question like this is going to pop up but i have no solutions to this question and no idea how to work it out the question is as follows Find the equations of the line L1 through the point with position vector (4,2,1) and parallel to the vector...

got a question Xn+1=X2n-4Xn+6 so from there we play arround with Xs and get roots of Xs =2 or 3 then we sub that into F'(x) giving answers of 2therefore unstable and 0therefore stable i understand all of the question apart from the stable and unstable part could someone please tell me why...

starting with the iterated map derived in the notes for calculating rootp(p>0) Xn+1=1/2(Xn+(p)/(Xn) calculate root 7 starting with x0=1 so ok starting with that i get x0=1 x1=4 and then something strange happens the sub in looks like this X2=1/2(4+2/4)=9/4 i was under the...

brilliant why don't i see these things

.. no not X'' like X with 2 dots above it but i can't write that on here X

linearise the euqations near each equilibrium point? Write each of the following differential equations as two first order equations, find all the equlibrium points, and linearise the equations near each equlibrium point (a) X.. +x -1/4X3=0 first part done getting X.=y and Y.=-x+1/4X3...

Iv'e got an exam in like 2 weeks and i don't have any material on how to do this question so i know the forum says i should make an attempt at the question but i really don't have a clue where to start could someone run me through it please so i will be able to answer it and others like it in...