Homework Statement
A 200 MHz signal is to be transmitted over a point-to-point wireless link. Assume the earth’s surface is flat over the entire propagation distance, and is 700 metres above sea level. The transmitter is at ground level, and the receiver is situated on top of a multi-storey...
Homework Statement
The switch in the circuit in the figure has been open a long time before closing at t=0.
Find iL(t) t>0
Express your answer in terms of t, where t is in milliseconds.
https://www.flickr.com/photos/84781786@N03/8899251427/
The Attempt at a Solution
We simplify...
I just copied the function off the question, I'm assuming it's negative
Therefore
V(t)=3<-60
I(t)=39.439√2<-20.4
Z= V/I
=.0537<-39.6
X=3/29.432sqrt(2)sin(-40.4)
.0537 -j0.03486
Is that part correct
Homework Statement
Use source transformation on the voltage source and series-connected impedance for the circuit shown here to find the equivalent current source and parallel-connected impedance. Continue the simplification by combining the two parallel current sources into an equivalent...
Is this what your trying to say ?
So Vrms = 3/√2
Therefore solve for Irms
which is 54 = 3/√2Icos(40.1)
I=1.66
Z=(3/√2) / 1.66
Then find Z but you don't have an imaginary part ?
Homework Statement
The load (Z) in the circuit below absorbs a complex power of 54+j46 VA when the voltage across it is 3cos(400t+-60)V. Use this information to determine the impedance of the loadHomework Equations
P = V^2 / Z
The Attempt at a Solution
first convert V to polar form
3 <...
Homework Statement
A load operates at a voltage of Vx = 125V-rms and absorbs P = 55W andQ = 26VAR of power. Use this information to calculate the apparent power (S) and the power factor (pf) for the load.
Homework Equations
S = sqrt [ P^2 + Q^2]
pf = P / S
The Attempt at a...
Homework Statement
Calculate the average power (P) absorbed by the load shown below when its impedance is 56 +j15 ohms 21 A rms?
Answer to three significant figures
Homework Equations
P=Irms^2*RThe Attempt at a Solution
Converting 56 +j15 to polar form yields 57.9741 ohms @ 14.9951 degrees...
Homework Statement
power factor leading or lagging
v(t)=3.5cos(600t-120)
i(t)=2.3sin(600t+45)
Homework Equations
pf=cos(Vθ-Iθ)
The Attempt at a Solution
pf=cos(-75)
=.25881905
I get confused, How do we figure out whether it leads or lags.
Homework Statement
http://www.flickr.com/photos/84781786@N03/8687383259/in/photostream/
Homework Equations
Vc=Vsource*Zeq/(200+Zeq)
The Attempt at a Solution
Is this the correct way to get Zeq
100Ω and inductor as series . so we
100+j100 parallel with the capacitor. which...