Is this the right way to find Zeq for parallel circuit

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SUMMARY

The discussion focuses on calculating the equivalent impedance (Zeq) for a parallel circuit involving a 100Ω resistor and an inductor in series with a capacitor. The user applied the formula Vc=Vsource*Zeq/(200+Zeq) and attempted to find Zeq using the combination of impedances, resulting in a value of 400Ω. The solution was confirmed to have the correct magnitude but lacked appropriate units, which is crucial for accurate submission. Clarification on the multiplication of the Vsource value was also sought, indicating a need for understanding its application in the context of the equation.

PREREQUISITES
  • Understanding of complex impedance in AC circuits
  • Familiarity with series and parallel circuit configurations
  • Knowledge of phasor representation of voltages and currents
  • Proficiency in using impedance formulas such as Vc=Vsource*Zeq/(200+Zeq)
NEXT STEPS
  • Study the calculation of equivalent impedance in parallel circuits
  • Learn about the significance of units in electrical engineering calculations
  • Explore the use of phasors in AC circuit analysis
  • Investigate the impact of varying Vsource on circuit behavior
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing AC circuits and impedance calculations will benefit from this discussion.

pokie_panda
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Homework Statement


attachment.php?attachmentid=58319&stc=1&d=1367181165.jpg

http://www.flickr.com/photos/84781786@N03/8687383259/in/photostream/

Homework Equations



Vc=Vsource*Zeq/(200+Zeq)


The Attempt at a Solution



Is this the correct way to get Zeq
100Ω and inductor as series . so we
100+j100 parallel with the capacitor. which is -j100
so we use the formula Z1 + Z2//Z3
which we get 400

Is this correct
Also how do we multiply the Vsource value ?
 

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pokie_panda said:

Homework Statement


[PLAIN]http://www.flickr.com/photos/84781786@N03/8687383259/in/photostream/
http://www.flickr.com/photos/84781786@N03/8687383259/in/photostream/

Homework Equations



Vc=Vsource*Zeq/(200+Zeq)


The Attempt at a Solution



Is this the correct way to get Zeq
100Ω and inductor as series . so we
100+j100 parallel with the capacitor. which is -j100 \leftarrow should be -j200?
so we use the formula Z1 + Z2//Z3
which we get 400

Is this correct
Your description is a bit hard to follow, but it looks like you've got the right procedure. Your result has the correct magnitude, but lacks the appropriate units (that would lose you marks if submitted that way!).
Also how do we multiply the Vsource value ?
Multiply the Vsource? For what purpose?
 
Last edited by a moderator:
I ended up getting the correct solution , thanks for your help
 

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