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Is this the right way to find Zeq for parallel circuit

  1. Apr 28, 2013 #1
    1. The problem statement, all variables and given/known data
    attachment.php?attachmentid=58319&stc=1&d=1367181165.jpg
    http://www.flickr.com/photos/84781786@N03/8687383259/in/photostream/ [Broken]

    2. Relevant equations

    Vc=Vsource*Zeq/(200+Zeq)


    3. The attempt at a solution

    Is this the correct way to get Zeq
    100Ω and inductor as series . so we
    100+j100 parallel with the capacitor. which is -j100
    so we use the formula Z1 + Z2//Z3
    which we get 400

    Is this correct
    Also how do we multiply the Vsource value ?
     

    Attached Files:

    Last edited by a moderator: May 6, 2017
  2. jcsd
  3. Apr 28, 2013 #2

    gneill

    User Avatar

    Staff: Mentor

    Your description is a bit hard to follow, but it looks like you've got the right procedure. Your result has the correct magnitude, but lacks the appropriate units (that would lose you marks if submitted that way!).
    Multiply the Vsource? For what purpose?
     
    Last edited by a moderator: May 6, 2017
  4. Apr 28, 2013 #3
    I ended up getting the correct solution , thanks for your help
     
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