Recent content by Proofrific
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Graduate Integral of Product of Three Cosines
Thanks! That answered my question. For others, if a+b+c = 0, or a+b-c=0, or a-b+c=0, or a-b-c=0, then we integrate cos(0) = 1 and get 1/4.- Proofrific
- Post #3
- Forum: Calculus
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Graduate Integral of Product of Three Cosines
[solved] Integral of Product of Three Cosines I'm trying to determine the integral of the product of three cosines: \int_0^\infty \cos \left( \frac{n \pi t}{T} \right) \cos \left( \frac{m \pi t}{T} \right) \cos \left( \frac{l \pi t}{T} \right) dt for n, m, l integers. Some of the results...- Proofrific
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- Integral Product
- Replies: 3
- Forum: Calculus
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How to Calculate When a Bowling Ball Will Begin to Roll Without Sliding
Whoops, sorry. I meant v = r \omega, but you did that right. My bad. I don't see any problems with what you did. It looks like you did it right. Perhaps the solution is wrong?- Proofrific
- Post #4
- Forum: Introductory Physics Homework Help
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How to Calculate When a Bowling Ball Will Begin to Roll Without Sliding
Check how you went from angular velocity (w) to translational velocity (v).- Proofrific
- Post #2
- Forum: Introductory Physics Homework Help
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Particle Takes Infinite Time to Reach Top of Potential Hill
Homework Statement A particle is moving in a potential V(R) = \frac{1}{2} \left( \frac{1}{R} - \frac{1}{R^2} \right)^2. If you plot this, is has a well at R = 1 with height V(1) = 0 and a hump at R = 2 with height V(2) = 1/32. Question: If a particle has energy 1/32, show that it takes...- Proofrific
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- Hill Infinite Particle Potential Time
- Replies: 1
- Forum: Advanced Physics Homework Help
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Basis Transformation for Wave Function
Thanks for the help! How do you know that L_zr=L_z\theta=0? The only thing I remember about L_z is how it acts on an eigenstate: L_z|l,m\rangle = m \hbar | l,m \rangle. How do you know how it acts on r, \theta, and \phi?- Proofrific
- Post #3
- Forum: Advanced Physics Homework Help
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Basis Transformation for Wave Function
Homework Statement It's not a homework problem. I'm reading my textbook (Sakurai's Modern QM), and I'm not sure about a step (eq 3.6.6 through 3.6.8). Here it is: We start with a wave function that's been rotated: \langle x' + y' \delta \phi, y' - x' \delta \phi, z' | \alpha \rangle Now...- Proofrific
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- Basis Function Transformation Wave Wave function
- Replies: 3
- Forum: Advanced Physics Homework Help
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Radial Equation for Two-Body Central Forces
I'm getting two different radial equations depending on when I plug in the angular momentum piece. Here's the Lagrangian: L = \frac{1}{2} \mu (\dot{r}^2 + r^2 \dot{\phi}^2) - U(r) The Euler-Lagrange equation for phi gives angular momentum (conserved), which can be solved for \dot{\phi}...- Proofrific
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- Central forces Forces Radial
- Replies: 1
- Forum: Advanced Physics Homework Help
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Graduate Square Roots of Complex Numbers: Which Method is Correct?
I'm not sure how to determine the "meaning" of a problem I'm working on. It comes from calculus of residues, where I'm trying to evaluate the integral: \int_0^\infty \frac{x^{\mu-1}}{x + 1} dx . So, I'm using the complex integral \oint \frac{z^{\mu-1}}{z + 1} dz , where the cut line...- Proofrific
- Post #4
- Forum: Topology and Analysis
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Calculating Position in Simple Harmonic Motion with Given Amplitude and Velocity
I'm going to assume that the particle acts like a mass on a spring. Then, we can solve this problem using conservation of energy. At the system's biggest displacement (3cm), there is no kinetic energy, so the total energy of the system is just the energy from the spring: E_{tot} =...- Proofrific
- Post #2
- Forum: Introductory Physics Homework Help
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Graduate Square Roots of Complex Numbers: Which Method is Correct?
I have two ways of evaluating (e^{i 2 \pi}) ^{1/2}, and they give me different answers. Which one is correct, and why is the other wrong? Method 1: (e^{i 2 \pi}) ^{1/2} = e^{i \pi} = -1 Method 2: (e^{i 2 \pi}) ^{1/2} = 1^{1/2} = 1- Proofrific
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- Complex Complex numbers Numbers
- Replies: 12
- Forum: Topology and Analysis
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Confusion: deriving momentum expectation value in QM
I have a question about why \left. x \left( \Psi^* \frac{\partial \Psi}{\partial x} - \frac{\partial \Psi^*}{\partial x} \Psi \right) \right|^{+\infty}_{-\infty} = 0. I understand that normalization requires that \Psi goes to zero at \pm \infty. But, what about the x in front of the...- Proofrific
- Post #6
- Forum: Advanced Physics Homework Help