Recent content by protivakid

Thanks for the reply, I didn't forget to put it in, I forgot to do it lol. I'm still learning how to do all these problems so even obvious hints make a world of difference to me. I managed to completely solve it from there so thank you.

Homework Statement \frac{4x^{4}-8x^{3}+5x^{2}-2x-1}{2x^{2}-3x-2} Homework Equations The Attempt at a Solution I started of by breaking the bottom part down into (2x+1)(x-2) which then allowed me to set... \frac{A}{(2x+1)}+\frac{B}{(x-2)} The problem is from here I tried...

Thanks, i'll try to take it from here but I don't think there is too much left to do.

I am trying to set up a triangle for visual aid, is the following correct... sin=e^x cos=sqrt(1-e^2x) tan= (e^x)/(sqrt(1-e^2x) Thanks guys, greatly appreciated.

Alright so taking your advice I set sin(theta) to e^x dx, and cos(theta) to sqrt(1-e^2x). That then gave me sin^3(theta)/cos((theta). I set u=sin(theta)d(theta) and du=cos(theta) which gave me u^3du^-1. That then became u^2/2 which is sin^2/2. My final answer U then got from that was e^2x/2 + c...

Homework Statement \int \frac{e^{3x}dx}{\sqrt{1-e^{2x}}} Homework Equations The Attempt at a Solution Alright so I am able to do other similar problems fine, I think it is the "e" that is throwing me off as well as the fact that the "x" is in the exponent. I started the...

so after putting the substitution back in I woild have 1/2\int2x/\sqrt{x2-1} correct?

tuche haha still any help ?

yes that is what I meant except outside of the \sqrt{} there is another x , that substitution is part of a much larger master problem but I have the rest figured out, I just need a helpful push into the right direction as far as solving this piece, thank you :).

Alright so I have a math problem that I have broken down into parts and one of my parts I am having trouble with is as follows. Homework Statement \oint(x2dx)/(x\sqrt{x2-1} Homework Equations The Attempt at a Solution I attempted to solve it by making z=x2-1 and dz=2xdx. From...

I did get the answer and to the last poster, it's not that I am not reading the advice, it's that I don't completely understand it so I take a shot at what i think it is based on what I got from the advice and then see if I understand it correctly or if I still need help. Thank you all though.

That helped a lot, would the final answer then be (1/ln(5)\sqrt{}2)tan-1(5sinx/\sqrt{}2) ? The only thing I was not sure about was the ln(5) as far as how to deal with that.

Anyone?

well if say I made u 25x would du = 5(2)4xdx? Thank you.

So going by that rule v = 25xln(2) right?